This is a challenge to all the Brilliant members. Using symbols make your answer to the question as 6. You can use symbols such as squares, plus, minus etc. An example of \(6\) is been done for you.

\( 0 0 0 = 6 \)

\( 1 1 1 = 6 \)

\( 2 2 2 = 6 \)

\( 3 3 3 = 6 \)

\( 4 4 4 = 6 \)

\( 5 5 5 = 6 \)

\( 6 + 6 - 6 = 6 \)

\( 7 7 7 = 6 \)

\( 9 9 9 = 6 \)

And finally \(8\) is toughest number where you have to use all the Symbols that you have used in all the above questions.

\( 8 8 8 = 6 \)

Please reshare and like this if you can and most important please upload your answer.

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## Comments

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TopNewestI'll post the first one: \( (0!+0!+0!)! = 6\)

All right, I'll post the "hard one": \((\sqrt { \frac { 8 }{ \sqrt { .\dot { 8 } } \sqrt { .\dot { 8 } } } } \quad )!=6\).

Note that \(.\dot { 8 } =0.888888....\)

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Correct! But for \(8\) you made it quite difficult. In a simpler way it can be \( 8 - \sqrt{\sqrt{8+8}}=6\). And for \(0\) it can also be \((\cos0+\cos0+\cos0)!=6\).

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Well, you threw me off by saying it's so difficult!

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If nobody else comes up with any of the other answers, I'll post them all pretty soon.

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don't tell me that you have taken it from scam school

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These are my answers

\((0!+0!+0!)!=6\)

\((1+1+1)!=6\)

\(2+2+2=6\)

\((3\times 3)-3=6\)

\((4-(4\div 4))!=6\quad or\quad 4+4-\sqrt { 4 } =6\)

\(5+(5\div 5)=6\quad or\quad { (5 }^{ 2 }+5)\div 5=6\)

\(7-(7\div 7)=6\quad or\quad { (7 }^{ 2 }-7)\div 7=6\)

\((\sqrt { 8+(8\div 8) } )!=6\quad or\quad 8-\sqrt { \sqrt { 8+8 } } =6\)

\((\sqrt { ((9\times 9)\div 9) } )!=6\)

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