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This is a challenge to all the Brilliant members. Using symbols make your answer to the question as 6. You can use symbols such as squares, plus, minus etc. An example of \(6\) is been done for you.

\( 0 0 0 = 6 \)

\( 1 1 1 = 6 \)

\( 2 2 2 = 6 \)

\( 3 3 3 = 6 \)

\( 4 4 4 = 6 \)

\( 5 5 5 = 6 \)

\( 6 + 6 - 6 = 6 \)

\( 7 7 7 = 6 \)

\( 9 9 9 = 6 \)

And finally \(8\) is toughest number where you have to use all the Symbols that you have used in all the above questions.

\( 8 8 8 = 6 \)

Please reshare and like this if you can and most important please upload your answer.

Note by Ashwin Korade
2 years, 11 months ago

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These are my answers

\((0!+0!+0!)!=6\)

\((1+1+1)!=6\)

\(2+2+2=6\)

\((3\times 3)-3=6\)

\((4-(4\div 4))!=6\quad or\quad 4+4-\sqrt { 4 } =6\)

\(5+(5\div 5)=6\quad or\quad { (5 }^{ 2 }+5)\div 5=6\)

\(7-(7\div 7)=6\quad or\quad { (7 }^{ 2 }-7)\div 7=6\)

\((\sqrt { 8+(8\div 8) } )!=6\quad or\quad 8-\sqrt { \sqrt { 8+8 } } =6\)

\((\sqrt { ((9\times 9)\div 9) } )!=6\) Ronak Agarwal · 2 years, 10 months ago

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don't tell me that you have taken it from scam school Alamuru Ganesh · 2 years, 11 months ago

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I'll post the first one: \( (0!+0!+0!)! = 6\)

All right, I'll post the "hard one": \((\sqrt { \frac { 8 }{ \sqrt { .\dot { 8 } } \sqrt { .\dot { 8 } } } } \quad )!=6\).

Note that \(.\dot { 8 } =0.888888....\) Michael Mendrin · 2 years, 11 months ago

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@Michael Mendrin Correct! But for \(8\) you made it quite difficult. In a simpler way it can be \( 8 - \sqrt{\sqrt{8+8}}=6\). And for \(0\) it can also be \((\cos0+\cos0+\cos0)!=6\). Ashwin Korade · 2 years, 11 months ago

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@Ashwin Korade Well, you threw me off by saying it's so difficult! Michael Mendrin · 2 years, 11 months ago

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@Michael Mendrin No, you made it little complex Ashwin Korade · 2 years, 11 months ago

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@Ashwin Korade No, you said it was "toughest" and so I figured that only a tough answer would do. How was i to know that a simpler answer was possible? ??

If nobody else comes up with any of the other answers, I'll post them all pretty soon. Michael Mendrin · 2 years, 11 months ago

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