Challenge:Balancing problem

I am not sure if this is a popular question but I hope you will respect my wishes and not Google it. If you have already heard it,either move on,or post a hint,or add a followup question.

You have \(5\) boxes of coins.\(4\) of them contain \(10\) gm coins and \(1\) of them contains \(11\) gm coins.Assuming you can weigh any weight using a balance,can you spot the box with the \(11\) gm coins by weighing only once?If yes,how?

Details and Assumptions: You can take coins out of the boxes if you like.

Note by Rahul Saha
4 years, 5 months ago

No vote yet
1 vote

  Easy Math Editor

MarkdownAppears as
*italics* or _italics_ italics
**bold** or __bold__ bold

- bulleted
- list

  • bulleted
  • list

1. numbered
2. list

  1. numbered
  2. list
Note: you must add a full line of space before and after lists for them to show up correctly
paragraph 1

paragraph 2

paragraph 1

paragraph 2

[example link](https://brilliant.org)example link
> This is a quote
This is a quote
    # I indented these lines
    # 4 spaces, and now they show
    # up as a code block.

    print "hello world"
# I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
MathAppears as
Remember to wrap math in \( ... \) or \[ ... \] to ensure proper formatting.
2 \times 3 \( 2 \times 3 \)
2^{34} \( 2^{34} \)
a_{i-1} \( a_{i-1} \)
\frac{2}{3} \( \frac{2}{3} \)
\sqrt{2} \( \sqrt{2} \)
\sum_{i=1}^3 \( \sum_{i=1}^3 \)
\sin \theta \( \sin \theta \)
\boxed{123} \( \boxed{123} \)

Comments

Sort by:

Top Newest

By saying "You can take coins out of the boxes if you like", do you mean that we can take them out while they're being balanced? Obviously that'd make it damn easy. Explain that statement!

Parth Thakkar - 4 years, 4 months ago

Log in to reply

That's very simple. If suppose the weight of the box weighed is 10 gm, then all the four boxes weighing 10 gm coins have equal number of coins. Just take the coins out of each box and count them.

Deepak Sharma - 4 years, 5 months ago

Log in to reply

Can you explain more clearly what you mean?Also,I never said that the number of coins must be equal.Don't make unwarranted assumptions.

Rahul Saha - 4 years, 5 months ago

Log in to reply

Can I assume the boxes have no mass?

Jihoon Kang - 2 years, 11 months ago

Log in to reply

You can, I suppose. Alternatively, you can assume the boxes have equal mass.

Rahul Saha - 2 years, 11 months ago

Log in to reply

×

Problem Loading...

Note Loading...

Set Loading...