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Chandrashaker limit

                   find me near    Chandrashaker limit                   M =  1.49*M☼ 

Body made up of  'n' particales, so

for spherical symmetric object we write 4/3 ΠR^3 = n(4/3 Πr^3) where R- radius of object; & r- radius of particle of object made from; R = r * (n^1/3) now, mass of object = M = nmass of particles

         M = n*m
  ζ = M/R = n*m / r *(n^1/3)
     = (m/r)*(n^2/3)
     = constant
taking m is the mass of neutron = 1.67*E^-27  
  &  r = E^-15
    (m/r)^-1 = 0.59*E^12

Now for Black Hole escape velocity is given by, c = (2GM/R)^1/2
so M/R = 0.6304E^27 M/R = (n^2/3)(m/r) n = [(M/R)(r/m)]^3/2 n = 0.733E^58

M = 1.2241*E^31 kg
M☼= 8.169*E^30 kg
M/ M☼ = 1.49

M =  1.49*M☼

Note by Sunil Jadhav
3 years, 11 months ago

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