```
find me near Chandrashaker limit M = 1.49*M☼
Body made up of 'n' particales, so
```

for spherical symmetric object we write
4/3 ΠR^3 = n*(4/3 Πr^3)
where R- radius of object;
& r- radius of particle of object made from;
R = r * (n^1/3)
now, mass of object = M = n*mass of particles

```
M = n*m
ζ = M/R = n*m / r *(n^1/3)
= (m/r)*(n^2/3)
= constant
taking m is the mass of neutron = 1.67*E^-27
& r = E^-15
(m/r)^-1 = 0.59*E^12
```

Now for Black Hole escape velocity is given by,
c = (2GM/R)^1/2

so M/R = 0.6304*E^27
M/R = (n^2/3)*(m/r)
n = [(M/R)*(r/m)]^3/2
n = 0.733*E^58

```
M = 1.2241*E^31 kg
M☼= 8.169*E^30 kg
M/ M☼ = 1.49
M = 1.49*M☼
```

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