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# Changing value of 'g' question...................

A pendulum was taken from place A to B.It was observed that it lost 150s each day.What is the value acceleration due to gravity at B???? g at A=9.8

Note by Rajath Krishna R
4 years, 5 months ago

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Is the answer 9.766 m/s^2 ? · 4 years, 5 months ago

but how to do it?????????? · 4 years, 5 months ago

Well let the time period of pendulum at A be T1 and at B be T2. wkt time lost by a pendulum in "t" secs is given by
$$\frac{T2-T1}{T2}\times t$$

Your question states that time lost is 150 s in a day i.e. in 86400 secs.

Hence 150= $$\frac{T2-T1}{T2}\times 86400$$
Using this you can find T2 in terms of T1.
You would get $$\frac{T1}{T2} =\frac{86250}{86400}$$
now you know that T1 is inversly propotional to $$\sqrt{gA}$$ and T2 is inversly proportional to $$\sqrt{gB}$$ therefore using it.
$$\frac{\sqrt{gB}}{\sqrt{gA}}=\frac{86250}{86400}$$ hence gB=0.9965308 * gA HENCE gB = 9.7660 m/s^2.

Let me know if the answer is corerect. · 4 years, 5 months ago

i dnt knw whether the ans is right bcoz this Q came in our phy exam 2 days ago and no one could do it.............our teacher didnt teach us that time period formula also..............anyway thanks for the ans......................r u trying for IIT?????? · 4 years, 5 months ago

IITJEE!! thats too tough.. I am weak at chemistry I'am trying though. btw i hope you got the other graph question that you askd. This answer i'am 90 percent sure. Let me know the answer once you get to know it. · 4 years, 5 months ago

kk....i will tell u if i get to know the correct ans........ · 4 years, 5 months ago

is it 158.11 · 4 years, 5 months ago

i think there will only be a small change............................points A and B are two places on earth.... · 4 years, 5 months ago

Solution provided by saurabh is correct. · 4 years, 5 months ago