A pendulum was taken from place A to B.It was observed that it lost 150s each day.What is the value acceleration due to gravity at B???? g at A=9.8

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TopNewestIs the answer 9.766 m/s^2 ? – Saurabh Dubey · 4 years, 5 months ago

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– Rajath Krishna R · 4 years, 5 months ago

but how to do it??????????Log in to reply

\(\frac{T2-T1}{T2}\times t\)Your question states that time lost is 150 s in a day i.e. in 86400 secs.

Hence 150=

\(\frac{T2-T1}{T2}\times 86400\)Using this you can find T2 in terms of T1.

You would get \(\frac{T1}{T2} =\frac{86250}{86400}\)

now you know that T1 is inversly propotional to \(\sqrt{gA}\) and T2 is inversly proportional to \(\sqrt{gB}\) therefore using it.

\(\frac{\sqrt{gB}}{\sqrt{gA}}=\frac{86250}{86400}\) hence gB=0.9965308 * gA HENCE gB = 9.7660 m/s^2.

Let me know if the answer is corerect. – Saurabh Dubey · 4 years, 5 months ago

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– Rajath Krishna R · 4 years, 5 months ago

i dnt knw whether the ans is right bcoz this Q came in our phy exam 2 days ago and no one could do it.............our teacher didnt teach us that time period formula also..............anyway thanks for the ans......................r u trying for IIT??????Log in to reply

– Saurabh Dubey · 4 years, 5 months ago

IITJEE!! thats too tough.. I am weak at chemistry I'am trying though. btw i hope you got the other graph question that you askd. This answer i'am 90 percent sure. Let me know the answer once you get to know it.Log in to reply

– Rajath Krishna R · 4 years, 5 months ago

kk....i will tell u if i get to know the correct ans........Log in to reply

is it 158.11 – Sawan Singh · 4 years, 5 months ago

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– Rajath Krishna R · 4 years, 5 months ago

i think there will only be a small change............................points A and B are two places on earth....Log in to reply

– Sridhar Thiagarajan · 4 years, 5 months ago

Solution provided by saurabh is correct.Log in to reply

– Saurabh Dubey · 4 years, 5 months ago

Hope so. by the way your profile pic is quite funny!!! :DLog in to reply