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Chemistry doubt

\(0.5\text{ g}\) sample of a sulphite salt was dissolved in \(200\text{ ml}\) and \(20\text{ ml}\) of this solution required \(10\text{ ml}\) of \(0.02\text{ M}\) acidified permanganate solution.Find the percentage by mass of sulphite in sulphite ore?

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Note by Shivam Mishra
1 year, 4 months ago

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My solution :

Let the number of moles of sulphite ions be \(M\). Clearly on oxidation the sulphite ion changes to sulphate so the oxidation number changes from \(4+\) to \(6+\), hence the valence factor is \(2\). The product of moles and valence factor gives the equivalents. The valence factor permagnate solution in acidified solution is \(5\). Equate the equivalents as :

\[M ×2×\frac{20}{200} = \frac{10}{1000} × 0.02 × 5\]

\[M=\frac{5}{1000}\]

As molecular weight of sulphite ion is \(80\), percentage by mass is :

\[\frac{0.005 × 80}{0.5} × 100\] \[=80 %\]

Utkarsh Dwivedi - 1 year, 3 months ago

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Is the information complete?

Harsh Shrivastava - 1 year, 4 months ago

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Yes

Shivam Mishra - 1 year, 4 months ago

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80%

Yash Jain - 1 year, 1 month ago

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Thanks @Utkarsh Dwivedi

Shivam Mishra - 1 year, 3 months ago

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Tell me is this question based on molarity

Aakarshit Srivastava - 1 year, 3 months ago

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Yes,but it can also be solved using milliequivalents.

Shivam Mishra - 1 year, 3 months ago

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@Deeparaj Bhat @Prakhar Bindal please help!!!!

Shivam Mishra - 1 year, 4 months ago

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