Chemistry doubt

0.5 g0.5\text{ g} sample of a sulphite salt was dissolved in 200 ml200\text{ ml} and 20 ml20\text{ ml} of this solution required 10 ml10\text{ ml} of 0.02 M0.02\text{ M} acidified permanganate solution.Find the percentage by mass of sulphite in sulphite ore?

Please help!

Note by Shivam Mishra
3 years, 5 months ago

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My solution :

Let the number of moles of sulphite ions be MM. Clearly on oxidation the sulphite ion changes to sulphate so the oxidation number changes from 4+4+ to 6+6+, hence the valence factor is 22. The product of moles and valence factor gives the equivalents. The valence factor permagnate solution in acidified solution is 55. Equate the equivalents as :

M×2×20200=101000×0.02×5M ×2×\frac{20}{200} = \frac{10}{1000} × 0.02 × 5

M=51000M=\frac{5}{1000}

As molecular weight of sulphite ion is 8080, percentage by mass is :

0.005×800.5×100\frac{0.005 × 80}{0.5} × 100 =80%=80 \%

Utkarsh Dwivedi - 3 years, 4 months ago

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Is the information complete?

Harsh Shrivastava - 3 years, 5 months ago

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Yes

shivam mishra - 3 years, 5 months ago

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@Deeparaj Bhat @Prakhar Bindal please help!!!!

shivam mishra - 3 years, 5 months ago

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Tell me is this question based on molarity

Aakarshit Srivastava - 3 years, 4 months ago

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Yes,but it can also be solved using milliequivalents.

shivam mishra - 3 years, 4 months ago

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Thanks @Utkarsh Dwivedi

shivam mishra - 3 years, 4 months ago

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80%

yash jain - 3 years, 2 months ago

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