Chemistry doubt

0.5 g0.5\text{ g} sample of a sulphite salt was dissolved in 200 ml200\text{ ml} and 20 ml20\text{ ml} of this solution required 10 ml10\text{ ml} of 0.02 M0.02\text{ M} acidified permanganate solution.Find the percentage by mass of sulphite in sulphite ore?

Please help!

Note by Shivam Mishra
3 years, 2 months ago

No vote yet
1 vote

</code>...<code></code> ... <code>.">   Easy Math Editor

MarkdownAppears as
*italics* or _italics_ italics
**bold** or __bold__ bold

- bulleted
- list

  • bulleted
  • list

1. numbered
2. list

  1. numbered
  2. list
Note: you must add a full line of space before and after lists for them to show up correctly
paragraph 1

paragraph 2

paragraph 1

paragraph 2

[example link](https://brilliant.org)example link
> This is a quote
This is a quote
    # I indented these lines
    # 4 spaces, and now they show
    # up as a code block.

    print "hello world"
# I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
MathAppears as
Remember to wrap math in </span>...<span></span> ... <span> or </span>...<span></span> ... <span> to ensure proper formatting.
2 \times 3 2×3 2 \times 3
2^{34} 234 2^{34}
a_{i-1} ai1 a_{i-1}
\frac{2}{3} 23 \frac{2}{3}
\sqrt{2} 2 \sqrt{2}
\sum_{i=1}^3 i=13 \sum_{i=1}^3
\sin \theta sinθ \sin \theta
\boxed{123} 123 \boxed{123}

Comments

Sort by:

Top Newest

My solution :

Let the number of moles of sulphite ions be MM. Clearly on oxidation the sulphite ion changes to sulphate so the oxidation number changes from 4+4+ to 6+6+, hence the valence factor is 22. The product of moles and valence factor gives the equivalents. The valence factor permagnate solution in acidified solution is 55. Equate the equivalents as :

M×2×20200=101000×0.02×5M ×2×\frac{20}{200} = \frac{10}{1000} × 0.02 × 5

M=51000M=\frac{5}{1000}

As molecular weight of sulphite ion is 8080, percentage by mass is :

0.005×800.5×100\frac{0.005 × 80}{0.5} × 100 =80%=80 \%

Utkarsh Dwivedi - 3 years, 1 month ago

Log in to reply

Is the information complete?

Harsh Shrivastava - 3 years, 2 months ago

Log in to reply

Yes

shivam mishra - 3 years, 2 months ago

Log in to reply

@Deeparaj Bhat @Prakhar Bindal please help!!!!

shivam mishra - 3 years, 2 months ago

Log in to reply

Tell me is this question based on molarity

Aakarshit Srivastava - 3 years, 1 month ago

Log in to reply

Yes,but it can also be solved using milliequivalents.

shivam mishra - 3 years, 1 month ago

Log in to reply

Thanks @Utkarsh Dwivedi

shivam mishra - 3 years, 1 month ago

Log in to reply

80%

yash jain - 2 years, 12 months ago

Log in to reply

×

Problem Loading...

Note Loading...

Set Loading...