This discussion board is a place to discuss our Daily Challenges and the math and science
related to those challenges. Explanations are more than just a solution — they should
explain the steps and thinking strategies that you used to obtain the solution. Comments
should further the discussion of math and science.

When posting on Brilliant:

Use the emojis to react to an explanation, whether you're congratulating a job well done , or just really confused .

Ask specific questions about the challenge or the steps in somebody's explanation. Well-posed questions can add a lot to the discussion, but posting "I don't understand!" doesn't help anyone.

Try to contribute something new to the discussion, whether it is an extension, generalization or other idea related to the challenge.

Stay on topic — we're all here to learn more about math and science, not to hear about your favorite get-rich-quick scheme or current world events.

Markdown

Appears as

*italics* or _italics_

italics

**bold** or __bold__

bold

- bulleted - list

bulleted

list

1. numbered 2. list

numbered

list

Note: you must add a full line of space before and after lists for them to show up correctly

exceptional case !!!
Despite of five unpaired electrons the complex is coulourless. It is explained in terms of extra stability of half filled configuration due to which energy involved in electronic transiition is having shorter wavelength then the visible spectrum.

d-d transition in [FeF6]3- are spin only and quite weak making it almost colorless.
however in [CoF6]3- d-d transition from t2g to eg falls under visible region giving it a consistent blue color.

We mostly see colors by charge transfer and dd transition. we never see that the transitions are quite weak or so. but yeah i know it must be an exceptional case.

And neverthless thanks for answering and BTW how much are you getting in the AITS?

let me give my explanation too ....High spin Fe3+ is likely with a weak field ligand like F-so this is a high spin d5 ion and no d→d transitions are possible from the 6
S ground state because there are no other
sextet states possible. In the case of Co3+, this is a high spin d6
ion and the 4
D ground
state is split into 4
Eg and 4
T2g states by the Oh crystal field. The only spin allowed
transition will be between these states

Easy Math Editor

This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.

When posting on Brilliant:

`*italics*`

or`_italics_`

italics`**bold**`

or`__bold__`

boldNote: you must add a full line of space before and after lists for them to show up correctlyparagraph 1

paragraph 2

`[example link](https://brilliant.org)`

`> This is a quote`

Remember to wrap math in`\(`

...`\)`

or`\[`

...`\]`

to ensure proper formatting.`2 \times 3`

`2^{34}`

`a_{i-1}`

`\frac{2}{3}`

`\sqrt{2}`

`\sum_{i=1}^3`

`\sin \theta`

`\boxed{123}`

## Comments

Sort by:

TopNewestexceptional case !!! Despite of five unpaired electrons the complex is coulourless. It is explained in terms of extra stability of half filled configuration due to which energy involved in electronic transiition is having shorter wavelength then the visible spectrum.

Log in to reply

@Aniket Sanghi @Archit Agrawal @Samarth Agarwal @Aditya Chauhan @neelesh vij @Hargun Singh @Prince Loomba

sorry for mass tagging

Log in to reply

Abhi coordination chal raha hai

Log in to reply

Friday tak khatam hoga, And maybe this will be studied in d block

Log in to reply

Log in to reply

tune mujhe tag nahi kiya ! :(

Log in to reply

bhul gya tha :P

Log in to reply

K, let it go . i know i am stupid ! by the way best of luck for NSEP !

Log in to reply

Log in to reply

d-d transition in [FeF6]3- are spin only and quite weak making it almost colorless. however in [CoF6]3- d-d transition from t2g to eg falls under visible region giving it a consistent blue color.

Log in to reply

Yep that can be explained. but..

We mostly see colors by charge transfer and dd transition. we never see that the transitions are quite weak or so. but yeah i know it must be an exceptional case.

And neverthless thanks for answering and BTW how much are you getting in the AITS?

Log in to reply

Well. This one didn't go well. No ideas why i performed so bad. What's your rank ?

Log in to reply

what about you? And whats highest rank at your centre

Log in to reply

let me give my explanation too ....High spin Fe3+ is likely with a weak field ligand like F-so this is a high spin d5 ion and no d→d transitions are possible from the 6 S ground state because there are no other sextet states possible. In the case of Co3+, this is a high spin d6 ion and the 4 D ground state is split into 4 Eg and 4 T2g states by the Oh crystal field. The only spin allowed transition will be between these states

Log in to reply

i do not know how to write sub-script or superscript !

Log in to reply