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let me give my explanation too ....High spin Fe3+ is likely with a weak field ligand like F-so this is a high spin d5 ion and no d→d transitions are possible from the 6
S ground state because there are no other
sextet states possible. In the case of Co3+, this is a high spin d6
ion and the 4
D ground
state is split into 4
Eg and 4
T2g states by the Oh crystal field. The only spin allowed
transition will be between these states

d-d transition in [FeF6]3- are spin only and quite weak making it almost colorless.
however in [CoF6]3- d-d transition from t2g to eg falls under visible region giving it a consistent blue color.

We mostly see colors by charge transfer and dd transition. we never see that the transitions are quite weak or so. but yeah i know it must be an exceptional case.

And neverthless thanks for answering and BTW how much are you getting in the AITS?

exceptional case !!!
Despite of five unpaired electrons the complex is coulourless. It is explained in terms of extra stability of half filled configuration due to which energy involved in electronic transiition is having shorter wavelength then the visible spectrum.

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This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.

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TopNewestlet me give my explanation too ....High spin Fe3+ is likely with a weak field ligand like F-so this is a high spin d5 ion and no d→d transitions are possible from the 6 S ground state because there are no other sextet states possible. In the case of Co3+, this is a high spin d6 ion and the 4 D ground state is split into 4 Eg and 4 T2g states by the Oh crystal field. The only spin allowed transition will be between these states

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i do not know how to write sub-script or superscript !

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d-d transition in [FeF6]3- are spin only and quite weak making it almost colorless. however in [CoF6]3- d-d transition from t2g to eg falls under visible region giving it a consistent blue color.

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Yep that can be explained. but..

We mostly see colors by charge transfer and dd transition. we never see that the transitions are quite weak or so. but yeah i know it must be an exceptional case.

And neverthless thanks for answering and BTW how much are you getting in the AITS?

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Well. This one didn't go well. No ideas why i performed so bad. What's your rank ?

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what about you? And whats highest rank at your centre

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tune mujhe tag nahi kiya ! :(

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bhul gya tha :P

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K, let it go . i know i am stupid ! by the way best of luck for NSEP !

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exceptional case !!! Despite of five unpaired electrons the complex is coulourless. It is explained in terms of extra stability of half filled configuration due to which energy involved in electronic transiition is having shorter wavelength then the visible spectrum.

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@Aniket Sanghi @Archit Agrawal @Samarth Agarwal @Aditya Chauhan @neelesh vij @Hargun Singh @Prince Loomba

sorry for mass tagging

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Abhi coordination chal raha hai

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Friday tak khatam hoga, And maybe this will be studied in d block

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