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This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.

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## Comments

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TopNewestFour. They are methyl-propene (or isobutene), cis 2-butene, trans 2-butene and 1-butene (or simply butene).

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Can there be any cyclic isomers for this compound?

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Yes, but he specifies what kinds of isomers he wants (alkenes). C4H8 would be a cyclic alkane.

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Yes, but he specifies what kinds of isomers he wants (alkenes).Log in to reply

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Quite fast at chemistry. Good!!!

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Isn't this a question of NSEJS???

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Yes,how much you are scoring in NSEJS ?

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140 and if this answer ( I have done 4) is correct then 143 and what about you... We will have a common cutoff of Rajasthan...

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Arent u the one who got state rank 1 in IMO??

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C4H8 have 4 isomers

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C4H8 have 3 isomer, they are : H2C = CH – CH2– CH3 1-butena H3C - CH = CH– CH3 2-butena H2C = C – CH3 2-metilpropena I CH3

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What about cis/trans isomers of 2-butene? Also I think you've wronged when writing methyl-propene's formula.

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but-1-ene, but-2-ene, cyclobutane, methylcyclopropane, cis-2-butene, trans-2-buteneLog in to reply

He clearly specifies: he only wants the alkenes.

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oh sorry there are 5 isomers then but-1-ene, but-2-ene, 2-methyl propene, cis-2-butene, trans-2-butene,Log in to reply

which one ..structural or all?

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6 including the 2 cyclic isomers

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