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ABCD is a rectangle in which AB=CD=8cm,AD=BC=4cm.Taking AB and DC as diameter two semi circles are drawn which intersects DC at E and AB at F.Find the area of the intersecting circle. Ans-19.66cm^2

Note by Sushruta Dey 4 years, 10 months ago

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hi the area of the rectangle is 32 cm²

the area of wich one of the semi circles is 4²/2 pi= 8 pi

the area of the rectangle that is covered by only one semi circle will be called x

the one that is covered by both the semi circles is y and the one covered by no circle z

we can see clearly that 4x+2z+y=32

x+z=16-4pi

2x+y=8p

by solving the system we find the answer: y=16pi-32

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TopNewesthi the area of the rectangle is 32 cm²

the area of wich one of the semi circles is 4²/2 pi= 8 pi

the area of the rectangle that is covered by only one semi circle will be called x

the one that is covered by both the semi circles is y and the one covered by no circle z

we can see clearly that 4x+2z+y=32

x+z=16-4pi

2x+y=8p

by solving the system we find the answer: y=16pi-32

Log in to reply