In a triangle PQR, PQ= 12 cm, QR=10 cm and PR= 8 cm, a circle is inscribed touching PQ in L,QR in M and PR in N .

FIND ::::: PL , QM and RN

No vote yet

1 vote

×

Problem Loading...

Note Loading...

Set Loading...

## Comments

Sort by:

TopNewestif we take PL as x,QM as y and RN as z

then we can see that x+y=12 x+z=10 y+z=8

on solving we get x=5 y=7 z=3

Log in to reply

+1. The key to deriving the equations stems from knowing/proving the lengths of the tangents from the same point are equal.

Log in to reply

I also did same!

Log in to reply

thanks bro

Log in to reply

just saying about the question.......isnt it 10 th standard cbse maths book exercise question of chapter circles?

Log in to reply

You can generalize with side lengths a, b, c as

x + y = a

y + z = b

z + x = c

Adding, x + y + z = (a + b + c)/2 = s

So required lengths are \( \boxed {(s - a), (s - b), (s - c)} \)

Log in to reply