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Given that the angles a, b and c are connected by relation. 2\(tan^{2}\)a\(tan^{2}\)b\(tan^{2}\)c+\(tan^{2}\)a\(tan^{2}\)b\(tan^{2}\)c+\(tan^{2}\)c\(tan^{2}\)a=1

Find the value of \(sin^{2}\)a+\(sin^{2}\)b+\(sin^{2}\)c.

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Note by Swapnil Rajawat
2 years, 2 months ago

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