×

# complex inequalities

hey, I really want an answer ! do we have inequalities in complex numbers field, or not ? if yes, do we consider i the imaginary number as a positive or negative number ?!!

Note by Peace Trap
3 years, 8 months ago

MarkdownAppears as
*italics* or _italics_ italics
**bold** or __bold__ bold
- bulleted- list
• bulleted
• list
1. numbered2. list
1. numbered
2. list
Note: you must add a full line of space before and after lists for them to show up correctly
paragraph 1paragraph 2

paragraph 1

paragraph 2

[example link](https://brilliant.org)example link
> This is a quote
This is a quote
    # I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
# I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
MathAppears as
Remember to wrap math in $$...$$ or $...$ to ensure proper formatting.
2 \times 3 $$2 \times 3$$
2^{34} $$2^{34}$$
a_{i-1} $$a_{i-1}$$
\frac{2}{3} $$\frac{2}{3}$$
\sqrt{2} $$\sqrt{2}$$
\sum_{i=1}^3 $$\sum_{i=1}^3$$
\sin \theta $$\sin \theta$$
\boxed{123} $$\boxed{123}$$

Sort by:

No, we don't have inequality in complex nos... Bcz if we try to work upon an inequality... We finally get to know that there is a contradiction... And what we assumed was wrong... Ex..LET # i > i-1 # i² > i² + 1 - 2i # 1/2 < i

# That's not possible

:)

- 3 years, 8 months ago

$$\sqrt{-1}$$ is not a real number, so we cannot apply definitions of positive and negative numbers.

Suppose $$\sqrt{-1}$$ is negative or positive. Then $$\sqrt{-1}^2$$ will be obviously a positive number. Turns out $$-1 > 0$$ is a false statement, thus the imaginary unit is not negative or positive.

- 3 years, 8 months ago

will, but in simple other words is 5i>4i or 5i<4i or that's impossible !

- 3 years, 8 months ago