If a complex number *z* satisfies the equation \( z + \sqrt{2}|z+1| + i = 0 \) , then |*z*| is equal to (where *i* is the imaginary number)
a) 1
b) 2
c) \( \sqrt{5} \)
d) \( \sqrt{3} \)

*z* satisfies the equation \( z + \sqrt{2}|z+1| + i = 0 \) , then |*z*| is equal to (where *i* is the imaginary number)
a) 1
b) 2
c) \( \sqrt{5} \)
d) \( \sqrt{3} \)

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## Comments

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TopNewesti think the answer is \(\sqrt{5}\) – Prabhanjan Mannari · 4 years, 3 months ago

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the complex number must be of the form a-i where a is any real number now put it in the eqn n sove for d value of a n get mod z... – Aditya Chauhan · 4 years, 3 months ago

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The thing is...I solved this question some time back and I got \( \sqrt(5) \) as the answer...But now I'm totally stumped!!How did you do it? – Srujana Rao Yarasi · 4 years, 3 months ago

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– Nishant Sharma · 4 years, 3 months ago

That is pretty straightforward. Since the equation is simple, so we can substitute z= x + iy and express L.H.S as a + ib and compare it with R.H.S i.e 0 + i0 .Log in to reply