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guys help me

at what distance from the base of a right circular cone must the plane be passed parallel to the base in order that the volume of the frustum formed shall be three fifths of the volume of the given cone

Note by Jeriel Villa
2 years, 8 months ago

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Picture the cone with the vertex at the top. A plane parallel to the base which cuts this cone turns it into the frustrum and a smaller cone on top. From your conditions the volume of thus small cone is \( \dfrac {2}{5} \) the volume of the initial cone. Considering similar shapes we see that the percentage change in the perpendicular height h is equal to the percentage change in the radius r. Using the formula for the volume of a cone this should be all you need Josh Rowley · 2 years, 8 months ago

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