The function \(x^{cosx}\) results in \(-1/π\) when\(x=-π\) but the graph shows that the function can not be negative? Why is it so? I know it seems to be a stupid question but please help me out

Yes, \(x^{\cos x} \) is equal to \( - \frac 1\pi \) when \(x = -\pi \), but does not mean that the graph \(y = x^{\cos x} \) is defined when it's near \(x = -\pi \)?

Similarly, \(\sqrt[3]{-1} = -1\), does that mean the domain of \(y = \sqrt[3]{x} \) includes numbers like -1?

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TopNewestYes, \(x^{\cos x} \) is equal to \( - \frac 1\pi \) when \(x = -\pi \), but does not mean that the graph \(y = x^{\cos x} \) is defined when it's near \(x = -\pi \)?

Similarly, \(\sqrt[3]{-1} = -1\), does that mean the domain of \(y = \sqrt[3]{x} \) includes numbers like -1?

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I see.. Thanks for the reply 👍

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