Place any number of colored boxes on the infinite plane. You have to connect similarly colored boxes, so boxes of each color form a single cycle (each colored box is connected to two similarly colored boxes).

Given that boxes do not touch each other, prove that it is always possible to connect the boxes in this manner such that there are no intersections between the connecting lines.

Inspired by Connecting Colored Boxes. However, that problem is different in nature because it is contained in a finite plane and some boxes are on the edge of that plane.

No vote yet

1 vote

×

Problem Loading...

Note Loading...

Set Loading...

Easy Math Editor

`*italics*`

or`_italics_`

italics`**bold**`

or`__bold__`

boldNote: you must add a full line of space before and after lists for them to show up correctlyparagraph 1

paragraph 2

`[example link](https://brilliant.org)`

`> This is a quote`

Remember to wrap math in \( ... \) or \[ ... \] to ensure proper formatting.`2 \times 3`

`2^{34}`

`a_{i-1}`

`\frac{2}{3}`

`\sqrt{2}`

`\sum_{i=1}^3`

`\sin \theta`

`\boxed{123}`

## Comments

Sort by:

TopNewestConnect the boxes of the same color in a cycle (in any order). Do it for all colors. Then all nodes have degree \(2\). Hence by Kuratowski's theorem the resulting graph is planar.

Log in to reply

Hey Hello!

Log in to reply

Hey! I want to know something about you....How did you get to MIT ?means by giving SAT or something else...

Log in to reply

Hey Daniel Liu! your post looksgood as always but oftenly your image does'nt read correctly on my phone, the picture did'nt show up. So try to change the web you are saving those picture, i think it's.. not only happen to me.

Log in to reply

Chances are, if the image isn't reading, then it's a problem on your phone or on brilliant's phone app. Sorry for the inconvenience :\

Log in to reply