(3^2017)^2-(3^2015) / (3^2018)^2 - 3^2016)^2

I chose 1/9 as the answer, and so did the author, but the computer said it was wrong. This should be corrected!

Note by David David
10 months, 1 week ago

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Thanks for pointing it out. We have accidentally changed the answer. I've updated the answer. Those who previously answered $$\frac19$$ has been marked correct.

In the future, if you have concerns about a problem's wording/clarity/etc., you can report the problem. See how here.

Staff - 10 months, 1 week ago

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