# Latex

$$\Huge{\text{tan }\theta = \dfrac{\text{opposite}}{\text{hypotenuse}}}$$

$\red{\empty{\text{Z}}}$

$\mathbb{HELLO, hello}$

$\Huge{\mathbb{INFINITY}}$

$\Huge{\infty}$

$\text{If }\dfrac{x-a}{b+c}+\dfrac{x-b}{c+a}+\dfrac{x-c}{a+b} = 3, \text{then the value of x is}$

(a) $abc$

(b) $\dfrac{1}{abc}$

(c) $a+b+c$

(d) $\dfrac{1}{a+b+c}$

How did we get $\text{Area of segment =} \dfrac{\theta}{360}\pi r^2 - \displaystyle\frac{1}{2}r^2 sin\theta$

$\boxed{\LaTeX}$

$\rightarrow \Rightarrow$

$\text{How do we get this: area of isosceles triangle = }\dfrac{1}{2} r^2sin\theta \text{(where r is the equal side and }\theta \text{ is the vertex angle)}$

A body of mass 40 kilograms is moving on a surface with a constant velocity. If the constant of kinetic friction between the body and the surface is 0.329, find the friction between them. (Take $g = 10\frac{m}{s^2}$)

$P(\text{Dominant pattern}) = \dfrac{1}{2}$

$P(\text{Dominant legs}) = \dfrac{3}{4}$

$P(\text{Dominant eyes}) = 1$

 $P$ $p$ $L$ $l$ $E$ $e$ $p$ $Pp$ $pp$ $L$ $LL$ $Ll$ $E$ $EE$ $Ee$ $p$ $Pp$ $pp$ $l$ $Ll$ $ll$ $E$ $EE$ $Ee$

$P(\text{All dominant features}) = \dfrac{3}{4} \times \dfrac{1}{2} \times 1 = \dfrac{3}{8}$

Expected number of babies with only dominant features $= \dfrac{3}{8} \times 80 = 30$

Note by Aditya Mittal
5 months ago

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## Comments

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I’ve discovered the same thing ages ago haha :D

- 4 months, 3 weeks ago

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makes sense

- 4 months, 3 weeks ago

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@Kevin Long what do you mean?

- 4 months, 3 weeks ago

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who hasn't mushed their face against a mirror when they were three
just me?

- 4 months, 3 weeks ago

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Me too :D

- 4 months, 3 weeks ago

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