Solve: If y' denotes first derivative of y w.r.t. x and y'' denotes the second derivative of y w.r.t x, solve the differential equation: (cot y).y'' - (cosec y)^{2}.y' = 3log(sin y).

The brackets are simply brackets, not GIF or LIF or others.

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TopNewestI was waiting for someone to respond this but looks like no one is interested.

What I did was rewrite the given equation as:

\((\cot y\cdot y')'=3\log(\sin y) \)

But I couldn't proceed further.

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\((\cot y) y'' - (\csc^2 y ) y' = 3 \log(\sin y)\)

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