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# Differentiation show 2=1?

Given that $$6\times6 = 6+6+6+6+6+6$$, or equivalently
$$x\cdot x = x + x + x +x +x+x...$$, where $$x= 6$$.
Differentiate both sides with respect to $$x$$, we get
$$\dfrac{d}{dx} (x^2) = \dfrac d{dx} x + \dfrac d{dx} x + \dfrac d{dx} x + \dfrac d{dx} x + \dfrac d{dx} x + \dfrac d{dx} x...$$
$$2x = 1 + 1 + 1 + 1 + 1 + 1 ...= 1\cdot x$$
$$2x = x$$
$$2 = 1$$. why?

Note by Choi Chakfung
1 year ago

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You can't differentiate an equation until it's an identity. Also, both sides must be defined in the neighbourhood of the point at which you're differentiating. As these statements don't hold for the above equation, the proof is flawed. · 1 year ago

2x = 1 +1+1+1+1+1......(2x times) 2x =2x Not 2x=x So 2 not same with 1 · 11 months, 2 weeks ago

Brilliant Logo

· 12 months ago