Any sum of consecutive integers is divisible by p iff either the sum of terminal terms is divisible by p or the number of terms is divisible by p; terminal terms represent the first and last term and p is a prime number.

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TopNewestDo you want a proof or are you sharing this fact with us ? If it's the latter , I suggest don't make separate notes to share just one or two facts , post a note sharing around 10 -15 facts . That way , everyone will like to go thru your posts :) – Azhaghu Roopesh M · 1 year, 7 months ago

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– Aravind Vishnu · 1 year, 7 months ago

Thank you for the suggestion. I will try to make it better next time.Log in to reply

– Azhaghu Roopesh M · 1 year, 6 months ago

You are welcome \(\ddot\smile\)Log in to reply