Hi brilliant,

I've got a problem in question number **3.143** of the book **Problems in general physics** by **Irodov**.

The question states,

A parallel-plate capacitor was lowered into water in a horizontal, with water filling up the gap between the plates d meter wide. Then a constant voltage \(V\) was applied to the capacitor. Find the water pressure increment in the gap. Take relative permittivity of water as \(\varepsilon \).

I solved it as follows:

- Electrostatic pressure on a point in the capacitor before water was filled:

\({ P }_{ 1 }=\frac { 1 }{ 2 } { \varepsilon }_{ 0 }{ E }^{ 2 }=\frac { 1 }{ 2 } { \varepsilon }_{ 0 }{ \left( \frac { V }{ d } \right) }^{ 2 }\)

- Electrostatic pressure on a point in the capacitor before water was filled:

\({ P }_{ 2 }=\frac { 1 }{ 2 } { \varepsilon \varepsilon }_{ 0 }{ E }^{ 2 }=\frac { 1 }{ 2 } { \varepsilon \varepsilon }_{ 0 }{ \left( \frac { V }{ d } \right) }^{ 2 }\)

- Therefore increase in pressure = \(\Delta P=\frac { 1 }{ 2 } { \varepsilon }_{ 0 }\left( \varepsilon -1 \right) { \left( \frac { V }{ d } \right) }^{ 2 }\)

But the answer given in the solution is:

\(\Delta P=\frac { 1 }{ 2 } { \varepsilon }_{ 0 }\varepsilon \left( \varepsilon -1 \right) { \left( \frac { V }{ d } \right) }^{ 2 }\)

Please check if my solution is right. Please correct me.

## Comments

Sort by:

TopNewestYeah, dimensionally speaking, the given answer is wrong. Must be a typo. – Raj Magesh · 1 year, 9 months ago

Log in to reply

– Aditya Kumar · 1 year, 9 months ago

Can u verify my solution??Log in to reply

permittivity of wateris \(\epsilon\) or that therelativepermittivity of water is \(\epsilon\)? – Raj Magesh · 1 year, 9 months agoLog in to reply

– Raj Magesh · 1 year, 9 months ago

But your method is fine.Log in to reply

– Aditya Kumar · 1 year, 9 months ago

Thanks for reviewing it!Log in to reply

– Aditya Kumar · 1 year, 9 months ago

Relative permittivityLog in to reply

This looks like a typo to me, unless I'm missing something. – Josh Silverman Staff · 1 year, 9 months ago

Log in to reply

– Aditya Kumar · 1 year, 9 months ago

Sir what can u say about my method? Is it right?Log in to reply

– Josh Silverman Staff · 1 year, 9 months ago

I find no problem with your approach. I think your work is correct.Log in to reply

– Aditya Kumar · 1 year, 9 months ago

Thanks a lot sir!Log in to reply

@Josh Silverman @Ronak Agarwal @Mvs Saketh @Deepanshu Gupta @Calvin Lin @Best of Electricity and Magnetism @Nishant Rai @Atri Dutta @NILAY PANDE and others please help. – Aditya Kumar · 1 year, 9 months ago

Log in to reply