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Find the number of digits in $$\large2^{2^{22}}$$?

Note by Naitik Sanghavi
1 year, 4 months ago

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1262612 · 1 year, 4 months ago

Actually I got the answer but according to my book answer key I was wrong so....Thanks · 1 year, 4 months ago

@Dev Sharma DevBut how will you find the number of digits without computing $$\large2^{22}$$ if it is asked in exam? · 1 year, 4 months ago

U may assume the no. Of digits of a number be x. Let the number be a^b. So 10^(x-1) = a^b X-1 = blog(a) [log with base 10] X = blog(a) +1 For convenience, X = [blog(a)] +1 So 2^22 has [22log(2)] +1 digits.similarly following can be calculat ed · 1 year, 3 months ago

How to apply here .here it will become 2^22 log(2) then we have to apply log again then do antilog.after doing this I got answer 447 .is it right?????? · 1 year, 2 months ago