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Find the number of digits in \(\large2^{2^{22}}\)?

Note by Naitik Sanghavi
1 year, 12 months ago

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Dev Sharma - 1 year, 12 months ago

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Actually I got the answer but according to my book answer key I was wrong so....Thanks

Naitik Sanghavi - 1 year, 12 months ago

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@Dev Sharma DevBut how will you find the number of digits without computing \(\large2^{22}\) if it is asked in exam?

Naitik Sanghavi - 1 year, 12 months ago

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U may assume the no. Of digits of a number be x. Let the number be a^b. So 10^(x-1) = a^b X-1 = blog(a) [log with base 10] X = blog(a) +1 For convenience, X = [blog(a)] +1 So 2^22 has [22log(2)] +1 digits.similarly following can be calculat ed

Aditya Narayan Sharma - 1 year, 12 months ago

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@Aditya Narayan Sharma How to apply here .here it will become 2^22 log(2) then we have to apply log again then do antilog.after doing this I got answer 447 .is it right??????

Anshul Sanghi - 1 year, 10 months ago

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@Calvin Lin Please help me with this!

Naitik Sanghavi - 1 year, 12 months ago

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