Waste less time on Facebook — follow Brilliant.
×

Doubt! Please help!

Find the number of digits in \(\large2^{2^{22}}\)?

Note by Naitik Sanghavi
10 months, 1 week ago

No vote yet
1 vote

Comments

Sort by:

Top Newest

1262612 Dev Sharma · 10 months, 1 week ago

Log in to reply

@Dev Sharma Actually I got the answer but according to my book answer key I was wrong so....Thanks Naitik Sanghavi · 10 months, 1 week ago

Log in to reply

@Dev Sharma @Dev Sharma DevBut how will you find the number of digits without computing \(\large2^{22}\) if it is asked in exam? Naitik Sanghavi · 10 months, 1 week ago

Log in to reply

@Naitik Sanghavi U may assume the no. Of digits of a number be x. Let the number be a^b. So 10^(x-1) = a^b X-1 = blog(a) [log with base 10] X = blog(a) +1 For convenience, X = [blog(a)] +1 So 2^22 has [22log(2)] +1 digits.similarly following can be calculat ed Aditya Sharma · 10 months, 1 week ago

Log in to reply

@Aditya Sharma How to apply here .here it will become 2^22 log(2) then we have to apply log again then do antilog.after doing this I got answer 447 .is it right?????? Anshul Sanghi · 8 months, 3 weeks ago

Log in to reply

@Calvin Lin Please help me with this! Naitik Sanghavi · 10 months, 1 week ago

Log in to reply

×

Problem Loading...

Note Loading...

Set Loading...