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Prove that:

\[\frac {\sin 2x}{\cos^2 x} = 2\tan x\]

Note by Yan Yau Cheng 2 years, 9 months ago

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\(\dfrac{\sin 2x}{\cos^2x}=\dfrac{2\sin x\cos x}{\cos^2x}=\dfrac{2\sin x}{\cos x}=2\tan x\) – Trevor B. · 2 years, 9 months ago

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sin2x=2sinx.cosx /cosx^2=2.sinx/cosx=2.tanx – Rutvik Paikine · 2 years, 9 months ago

sin2x=2six.cosx sin2x/cosx^2=2.six/cosx=2.tanx – Subrata Saha · 2 years, 9 months ago

One line solution :D – Kïñshük Sïñgh · 2 years, 6 months ago

ANOTHER EASY QUESTION. – Kushagra Sahni · 2 years, 9 months ago

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## Comments

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TopNewest\(\dfrac{\sin 2x}{\cos^2x}=\dfrac{2\sin x\cos x}{\cos^2x}=\dfrac{2\sin x}{\cos x}=2\tan x\) – Trevor B. · 2 years, 9 months ago

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sin2x=2sinx.cosx /cosx^2=2.sinx/cosx=2.tanx – Rutvik Paikine · 2 years, 9 months ago

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sin2x=2six.cosx sin2x/cosx^2=2.six/cosx=2.tanx – Subrata Saha · 2 years, 9 months ago

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One line solution :D – Kïñshük Sïñgh · 2 years, 6 months ago

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ANOTHER EASY QUESTION. – Kushagra Sahni · 2 years, 9 months ago

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