recently, i tried to find electric field at surface of a charged dielectric and a conducting sphere without using guass law, rather using standard method of integration.... for dielectric sphere i got it right but for conducting one, dividing into thin rings and analysing the fields due to them i got the field less by a factor of 2 . please try to find field like this, and if you get correct, tell where i was missing. see the attachment... i forgot dtheta so i had to edit.... thanks in advance.....

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TopNewestit's not understandable frnd – Sahil Arora · 3 years, 3 months ago

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Just ignore it. I found what was wrong. – Jatin Yadav · 3 years, 3 months ago

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– Krishna Jha · 2 years, 11 months ago

Could you tell whats wrong??Log in to reply

– Jatin Yadav · 2 years, 11 months ago

Actually, I didn't add the electric field due to small charge just on the given point, adding which(\(\dfrac{\sigma}{2 \epsilon_{0}}\)), we get correct answer.Log in to reply

– Krishna Jha · 2 years, 11 months ago

Oh yes... Thanks.. :-)Log in to reply