Waste less time on Facebook — follow Brilliant.
×

electric field at surface of a conducting sphere...

recently, i tried to find electric field at surface of a charged dielectric and a conducting sphere without using guass law, rather using standard method of integration.... for dielectric sphere i got it right but for conducting one, dividing into thin rings and analysing the fields due to them i got the field less by a factor of 2 . please try to find field like this, and if you get correct, tell where i was missing. see the attachment... i forgot dtheta so i had to edit.... thanks in advance.....

Note by Jatin Yadav
4 years, 5 months ago

No vote yet
7 votes

Comments

Sort by:

Top Newest

it's not understandable frnd

Sahil Arora - 3 years, 6 months ago

Log in to reply

Well, I didn't know latex 10 months ago :P

Just ignore it. I found what was wrong.

Jatin Yadav - 3 years, 6 months ago

Log in to reply

Could you tell whats wrong??

Krishna Jha - 3 years, 2 months ago

Log in to reply

@Krishna Jha Actually, I didn't add the electric field due to small charge just on the given point, adding which(\(\dfrac{\sigma}{2 \epsilon_{0}}\)), we get correct answer.

Jatin Yadav - 3 years, 1 month ago

Log in to reply

@Jatin Yadav Oh yes... Thanks.. :-)

Krishna Jha - 3 years, 1 month ago

Log in to reply

×

Problem Loading...

Note Loading...

Set Loading...