Consider two conducting spheres of same radius \(r\), separated by a distance \(d\). Charges \(+q\) and \(-q\) are placed on the two spheres. Find the force \(F\) acting on one sphere due to the other.

No vote yet

1 vote

×

Problem Loading...

Note Loading...

Set Loading...

Easy Math Editor

`*italics*`

or`_italics_`

italics`**bold**`

or`__bold__`

boldNote: you must add a full line of space before and after lists for them to show up correctlyparagraph 1

paragraph 2

`[example link](https://brilliant.org)`

`> This is a quote`

Remember to wrap math in \( ... \) or \[ ... \] to ensure proper formatting.`2 \times 3`

`2^{34}`

`a_{i-1}`

`\frac{2}{3}`

`\sqrt{2}`

`\sum_{i=1}^3`

`\sin \theta`

`\boxed{123}`

## Comments

Sort by:

TopNewestCan you please elaborate the question?

Log in to reply

@Kishore S Shenoy There are two spherical conductors : one having charge +q and other -q. Find force of interaction between them ( as a function of their common radius r and distance between their centres d).

Log in to reply

Ohh, the separation is not large? I suppose that is the catch?

Log in to reply

@Kishore S Shenoy The separation is arbitary (of course, greater than 2r).

Log in to reply

Do you know the answer?

Log in to reply

@Kishore S Sheno Nope, I don't know the answer.

Log in to reply

Consider the charge centred at the centre. Force sud be q^2/(d+2r)^2

I am guessing. Am I right?

Log in to reply

No. The spheres are conducting. Hence, the charges distribute in such a way that the potential at the surface is equal radially symmetric.

Log in to reply