# Equivalent capacitance!

It's quite interesting!

4 years, 11 months ago

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Between which two points are we trying to find the equivalent capacitance?

- 4 years, 11 months ago

Assuming you mean between the leftmost two points, we have $$C_{eq} \approx 1.389260105247235 \cdot C$$.

Now, can anyone find a closed form for this?

- 4 years, 11 months ago

Can you tell me the process?

- 4 years, 11 months ago

I wrote a program to calculate $$C_{eq}(n)$$ for $$n = 1, \ldots, 100$$. The convergence was exponential, specifically $$C_{eq}(n) \approx (1.38926 - 0.80082 \cdot 0.07714^n)C$$.

While this doesn't solve anything, it might give someone a hint as to how to proceed.

- 4 years, 11 months ago

Are you sure if there exists closed-form solution?

- 4 years, 10 months ago