New user? Sign up

Existing user? Sign in

Factorize \[(a+2b-3c)^3 +(b+2c-3a)^3+(c+2a-3b)^3\]

Note by Abhishek Alva 11 months, 2 weeks ago

Sort by:

Let \((a+2b-3c)=x,(b+2c-3a)=y\) and \((c+2a-3b)=z.\)We can clearly see that \(x+y=z=0.\) So,\(x^3+y^3+z^3=3(a+2b-3c)(b+2c-3a)(c+2a-3b).\) – Ayush Rai · 11 months, 2 weeks ago

Log in to reply

ya your are right – Abhishek Alva · 11 months, 2 weeks ago

3(a+2b-3c)(b+2c-3a)(c+2a-3b) – Kaustubh Miglani · 11 months, 2 weeks ago

Problem Loading...

Note Loading...

Set Loading...

## Comments

Sort by:

TopNewestLet \((a+2b-3c)=x,(b+2c-3a)=y\) and \((c+2a-3b)=z.\)We can clearly see that \(x+y=z=0.\)

So,\(x^3+y^3+z^3=3(a+2b-3c)(b+2c-3a)(c+2a-3b).\) – Ayush Rai · 11 months, 2 weeks ago

Log in to reply

ya your are right – Abhishek Alva · 11 months, 2 weeks ago

Log in to reply

3(a+2b-3c)(b+2c-3a)(c+2a-3b) – Kaustubh Miglani · 11 months, 2 weeks ago

Log in to reply