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# Factorise

Factorize $(a+2b-3c)^3 +(b+2c-3a)^3+(c+2a-3b)^3$

Note by Abhishek Alva
5 months, 2 weeks ago

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Let $$(a+2b-3c)=x,(b+2c-3a)=y$$ and $$(c+2a-3b)=z.$$We can clearly see that $$x+y=z=0.$$
So,$$x^3+y^3+z^3=3(a+2b-3c)(b+2c-3a)(c+2a-3b).$$ · 5 months, 2 weeks ago

ya your are right · 5 months, 2 weeks ago