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Factorize \[(a+2b-3c)^3 +(b+2c-3a)^3+(c+2a-3b)^3\]

Note by Abhishek Alva 7 months, 2 weeks ago

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Let \((a+2b-3c)=x,(b+2c-3a)=y\) and \((c+2a-3b)=z.\)We can clearly see that \(x+y=z=0.\) So,\(x^3+y^3+z^3=3(a+2b-3c)(b+2c-3a)(c+2a-3b).\) – Ayush Rai · 7 months, 2 weeks ago

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ya your are right – Abhishek Alva · 7 months, 2 weeks ago

3(a+2b-3c)(b+2c-3a)(c+2a-3b) – Kaustubh Miglani · 7 months, 2 weeks ago

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TopNewestLet \((a+2b-3c)=x,(b+2c-3a)=y\) and \((c+2a-3b)=z.\)We can clearly see that \(x+y=z=0.\)

So,\(x^3+y^3+z^3=3(a+2b-3c)(b+2c-3a)(c+2a-3b).\) – Ayush Rai · 7 months, 2 weeks ago

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ya your are right – Abhishek Alva · 7 months, 2 weeks ago

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3(a+2b-3c)(b+2c-3a)(c+2a-3b) – Kaustubh Miglani · 7 months, 2 weeks ago

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