# Factorise

Factorize $(a+2b-3c)^3 +(b+2c-3a)^3+(c+2a-3b)^3$

Note by Abhishek Alva
1 year, 9 months ago

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## Comments

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Let $$(a+2b-3c)=x,(b+2c-3a)=y$$ and $$(c+2a-3b)=z.$$We can clearly see that $$x+y=z=0.$$
So,$$x^3+y^3+z^3=3(a+2b-3c)(b+2c-3a)(c+2a-3b).$$

- 1 year, 9 months ago

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ya your are right

- 1 year, 9 months ago

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3(a+2b-3c)(b+2c-3a)(c+2a-3b)

- 1 year, 9 months ago

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