Famous Exam Problem

Note by Talulah Riley
2 weeks, 1 day ago

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@Steven Chase Have a look. And also if possible, tell me the time you take to solve this. Thanks in advance.

Talulah Riley - 2 weeks, 1 day ago

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One more thing , please solve anaylitcally.

Talulah Riley - 2 weeks, 1 day ago

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@Karan Chatrath

Talulah Riley - 2 weeks, 1 day ago

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My attempt. I have not solved it completely.

Circuit equations are:

V1+L1I˙1+MI˙2+I1R1=0-V_1 + L_1 \dot{I}_1 + M\dot{I}_2 + I_1R_1=0 V2+L2I˙2+MI˙1+I2R2=0-V_2 + L_2 \dot{I}_2 + M\dot{I}_1 + I_2R_2=0

Now, I1(0)=I2(0)=0I_1(0) = I_2(0)=0. You need to solve the above set of differential equations and use that solution to compute the work done as follows:

W=0tf(V1I1+V2I2) dtW = \int_{0}^{t_f} (V_1I_1+V_2I_2) \ dt

Karan Chatrath - 2 weeks, 1 day ago

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@Karan Chatrath we can solve without solving differential equation also .I have solved it. It is a jee advance 2020 problem. A very fun problem

Talulah Riley - 2 weeks, 1 day ago

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@Karan Chatrath Here is the solution. In case you interested

Talulah Riley - 2 weeks, 1 day ago

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I do not think this is correct. This is because you have assumed that all work done by the battery is energy stored in the inductors. There is heat dissipated in the resistors also.

Karan Chatrath - 2 weeks, 1 day ago

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@Karan Chatrath I am using the formula for battey only P=ViP=Vi and intergrating pp w.r.t dtdt. , Can you use matlab for solving the problem. I am not 100% confident,about my answer. But in my opinion my approach is right.
Can you check? Most probably 55 is right answer, assuming coils in different direction.

Talulah Riley - 2 weeks, 1 day ago

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@Talulah Riley No, I do not think your approach is right. I have checked using code also. The work done by the battery continuously increases with time as the steady-state current flows through the resistors which continuously dissipate heat. You have just calculated the magnetic energy stored at steady state. That will obviously be constant, and that calculation is correct. But this quantity is not at all equal to the work done by the sources.

Karan Chatrath - 2 weeks, 1 day ago

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@Karan Chatrath @Karan Chatrath Yeah I think you are right.
What is the final answer. :(

Talulah Riley - 2 weeks, 1 day ago

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@Talulah Riley Actually, I have changed my opinion now. I was reading the question again, and it says ' total work done against induced emf of the inductors'. It does not say just 'total work done'. So I think your approach is correct. If the question was just 'total work done', then the answer is infinity because the steady-state is reached asymptotically, and also, the circuit draws energy from the source at steady state. But since work is done is against inductive loads, that amount of work done is stored as magnetic energy. I agree with you now. This is a tricky problem.

Karan Chatrath - 2 weeks, 1 day ago

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@Karan Chatrath @Karan Chatrath Yes Exactly that is what I also want to say.
jee advance is therefore the toughest exam in the world.
If you want to solve more questions like this you can download physics paper form here

Talulah Riley - 2 weeks, 1 day ago

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@Talulah Riley I think APhO (Asian Physics Olympiad) is slightly harder or about as hard as JEE Advanced. However, JEE Advanced is easily one of the most difficult engineering exams, and possibly the most competitive and difficult entrance exams for STEM in the world.

Krishna Karthik - 2 weeks, 1 day ago

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@Krishna Karthik @Krishna Karthik Yeah bro. You can solve Jee advance Question paper held on 27 September 2020,1 week ago .
Using above link you will get physics question paper there are 2 papers. Each paper contains 18 question .
Total 36 questions were there in the exam. I want to you to solve all mechanics question from that 36.

Talulah Riley - 2 weeks, 1 day ago

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