# Famous Exam Problem  Note by Talulah Riley
2 weeks, 1 day ago

This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.

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@Steven Chase Have a look. And also if possible, tell me the time you take to solve this. Thanks in advance.

- 2 weeks, 1 day ago

One more thing , please solve anaylitcally.

- 2 weeks, 1 day ago

- 2 weeks, 1 day ago

My attempt. I have not solved it completely.

Circuit equations are:

$-V_1 + L_1 \dot{I}_1 + M\dot{I}_2 + I_1R_1=0$ $-V_2 + L_2 \dot{I}_2 + M\dot{I}_1 + I_2R_2=0$

Now, $I_1(0) = I_2(0)=0$. You need to solve the above set of differential equations and use that solution to compute the work done as follows:

$W = \int_{0}^{t_f} (V_1I_1+V_2I_2) \ dt$

- 2 weeks, 1 day ago

@Karan Chatrath we can solve without solving differential equation also .I have solved it. It is a jee advance 2020 problem. A very fun problem

- 2 weeks, 1 day ago

@Karan Chatrath Here is the solution. In case you interested - 2 weeks, 1 day ago

I do not think this is correct. This is because you have assumed that all work done by the battery is energy stored in the inductors. There is heat dissipated in the resistors also.

- 2 weeks, 1 day ago

@Karan Chatrath I am using the formula for battey only $P=Vi$ and intergrating $p$ w.r.t $dt$. , Can you use matlab for solving the problem. I am not 100% confident,about my answer. But in my opinion my approach is right.
Can you check? Most probably 55 is right answer, assuming coils in different direction.

- 2 weeks, 1 day ago

No, I do not think your approach is right. I have checked using code also. The work done by the battery continuously increases with time as the steady-state current flows through the resistors which continuously dissipate heat. You have just calculated the magnetic energy stored at steady state. That will obviously be constant, and that calculation is correct. But this quantity is not at all equal to the work done by the sources.

- 2 weeks, 1 day ago

@Karan Chatrath Yeah I think you are right.
What is the final answer. :(

- 2 weeks, 1 day ago

Actually, I have changed my opinion now. I was reading the question again, and it says ' total work done against induced emf of the inductors'. It does not say just 'total work done'. So I think your approach is correct. If the question was just 'total work done', then the answer is infinity because the steady-state is reached asymptotically, and also, the circuit draws energy from the source at steady state. But since work is done is against inductive loads, that amount of work done is stored as magnetic energy. I agree with you now. This is a tricky problem.

- 2 weeks, 1 day ago

@Karan Chatrath Yes Exactly that is what I also want to say.
jee advance is therefore the toughest exam in the world.
If you want to solve more questions like this you can download physics paper form here

- 2 weeks, 1 day ago

I think APhO (Asian Physics Olympiad) is slightly harder or about as hard as JEE Advanced. However, JEE Advanced is easily one of the most difficult engineering exams, and possibly the most competitive and difficult entrance exams for STEM in the world.

- 2 weeks, 1 day ago

@Krishna Karthik Yeah bro. You can solve Jee advance Question paper held on 27 September 2020,1 week ago .
Using above link you will get physics question paper there are 2 papers. Each paper contains 18 question .
Total 36 questions were there in the exam. I want to you to solve all mechanics question from that 36.

- 2 weeks, 1 day ago