PQRS is a rectangle and XYTS is a square. Length and breadth of the rectangle is 18cm and 12cm respectively. Find the area of XYTS.

I need help to solve this problem. I do not know the right answer. You can post the solution in the comments section.

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TopNewestAssume the side of the square to be \(x.\)

Then \(PX\) = \(18-x\), \(XY\) = \(x\) , \(PS\) = \(18\) and \(SR\) = \(12.\)

\(\Delta PXY \sim \Delta PSR.\)

=> \(\frac{PX}{PS} = \frac{XY}{SR}\) => \(\frac{18-x}{18} = \frac{x}{12}\). => \(x = 7.2\) => \(x^{2} = 51.84\) – Rohit Camfar · 4 months, 2 weeks ago

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how did you get 50.44? – Ojasee Duble · 4 months, 1 week ago

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By the way, have you deactivated your slack account? I tried to reach you. – Ojasee Duble · 4 months, 2 weeks ago

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– Rohit Camfar · 4 months, 2 weeks ago

Nah!! I will talk with you on 10th of the month. The owner is busy in exam, and I am out here.Log in to reply

– Ojasee Duble · 4 months, 2 weeks ago

OkayLog in to reply

– Rohit Camfar · 4 months, 2 weeks ago

Now come. We all are active on the team.Log in to reply