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Note by Pi Han Goh 4 years, 4 months ago

$</code> ... <code>$</code>...<code>."> Easy Math Editor

*italics*

_italics_

**bold**

__bold__

- bulleted- list

1. numbered2. list

paragraph 1paragraph 2

paragraph 1

paragraph 2

[example link](https://brilliant.org)

> This is a quote

This is a quote

# I indented these lines # 4 spaces, and now they show # up as a code block. print "hello world"

2 \times 3

2^{34}

a_{i-1}

\frac{2}{3}

\sqrt{2}

\sum_{i=1}^3

\sin \theta

\boxed{123}

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Number of months with $29 , 30$ and $31$ days in $1001$ leap years.

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Wow that's quick!

Thanks.

awesome...

Genius!

Cool observation Sir!

amazing !

Take $x=1$ and by Chicken McNugget there exists $y,z$ such that $30y+31z=366337$.

That's the most straightforward way that immediately solves the problem as far as I know.

But Chicken McNugget didn't explicitly say that $y,z$ are positive.

It does; or else it would just degenerate to Bezout's Identity.

@Daniel Liu – OH wait it does! Silly me! Thanks! I've found the second simplest solution. Yay!

x=3955;y=4078;z=4171

x=3955;y=4078;z=4171;

see if HCF of 29,30,31 divides 366366 completely

Won't HCF of $29$, $30$ and $31$ be $1$?

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$</code> ... <code>$</code>...<code>."> Easy Math Editor

`*italics*`

or`_italics_`

italics`**bold**`

or`__bold__`

boldNote: you must add a full line of space before and after lists for them to show up correctlyparagraph 1

paragraph 2

`[example link](https://brilliant.org)`

`> This is a quote`

Remember to wrap math in $</span> ... <span>$ or $</span> ... <span>$ to ensure proper formatting.`2 \times 3`

`2^{34}`

`a_{i-1}`

`\frac{2}{3}`

`\sqrt{2}`

`\sum_{i=1}^3`

`\sin \theta`

`\boxed{123}`

## Comments

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TopNewestNumber of months with $29 , 30$ and $31$ days in $1001$ leap years.

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Wow that's quick!

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Thanks.

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awesome...

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Genius!

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Cool observation Sir!

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amazing !

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Take $x=1$ and by Chicken McNugget there exists $y,z$ such that $30y+31z=366337$.

That's the most straightforward way that immediately solves the problem as far as I know.

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But Chicken McNugget didn't explicitly say that $y,z$ are positive.

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It does; or else it would just degenerate to Bezout's Identity.

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x=3955;y=4078;z=4171

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x=3955;y=4078;z=4171;

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see if HCF of 29,30,31 divides 366366 completely

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Won't HCF of $29$, $30$ and $31$ be $1$?

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