Hello!

I guess the newest topic, Logic (Beta) , was introduced a month ago. Though I find members contributing to the section,but the contribution rate is very low. Apart from Mathematics and Physics, Logic should also be given equal importance. I would like to encourage the Brilliantians to contribute to the section with both easy and difficult problems. This would also give a chance to the members to level up and workout their brain!

Please do comment and share your views!
*...And keep Puzzling!*

No vote yet

1 vote

×

Problem Loading...

Note Loading...

Set Loading...

Easy Math Editor

`*italics*`

or`_italics_`

italics`**bold**`

or`__bold__`

boldNote: you must add a full line of space before and after lists for them to show up correctlyparagraph 1

paragraph 2

`[example link](https://brilliant.org)`

`> This is a quote`

Remember to wrap math in \( ... \) or \[ ... \] to ensure proper formatting.`2 \times 3`

`2^{34}`

`a_{i-1}`

`\frac{2}{3}`

`\sqrt{2}`

`\sum_{i=1}^3`

`\sin \theta`

`\boxed{123}`

## Comments

Sort by:

TopNewestNice suggestion

Log in to reply

Thank You very much!

Log in to reply

Okay, here's one

Propositio de homine et capra et lupo

(A proposition about the man, and a she-goat and the wolf)

A certain man needed to take a wolf, a she-goat and a load of cabbage across a river. However, he could only find a boat which would carry two of these at a time. Thus, what rule did he employ so as to get all of them across unharmed?

Now, this one is really old. But it's a start.

Log in to reply

Wouldn't it be "carry one of these at a time"? Otherwise the man would just take the wolf and cabbage across first and then go back for the she-goat, making for 3 crossings in total. If he can only take one at a time then I believe this would involve 7 crossings.

I was thinking of a variation of this, where the man has animals A,B,C,D,E, where A only eats B, B only eats C, C only eats D and D only eats E, (E is a vegetarian, or perhaps a vegan). If he can take a maximum of two animals at a time across the river, then I find that he can do it while keeping all the animals alive in 9 crossings, although I'm wondering if that is the minimum or not.

Log in to reply

This problem and wording actually dates back to year 782, Alcuin of York being the author of the book "Propositiones ad Acuendos Juvenes". That is the exact wording, as translated from Latin. By "carry two of these at a time", that includes the man, so unless the wolf, she-goat, or the cabbage can handle the boat, the man has to go on each trip and carry just one other with him. So, here's how it can go, from side A to side B

1) She-goat to B

2) Back to A

3) Wolf to B

4) She-goat back to A

5) Cabbage to B

6) Back to A

7) She-goat to B

Log in to reply

Log in to reply

Albert Einstein's Brain

Log in to reply

Log in to reply

yup..........................

nice thought...................:)

Log in to reply

Thank U! Please reshare if you like !

Log in to reply

i shared a problem...........

plz hv a try.......................

u can also check it on net and u will find different solutions........:)

Log in to reply

Log in to reply

but i didn't got the exact solution or logic behind it.................

Log in to reply

@Sravanth Chebrolu It was a honour for me to gain your like!

Log in to reply

Nah! No need to mention.

And I'll surely try posting problems on that topic \(\huge\ddot\smile\)!!!

Log in to reply

Thank You!

Log in to reply

I have also posted a series in this section, please check it out. If you like it pls reshare it

Log in to reply

@Sravanth Chebrolu @Aditya Chauhan and @Rajdeep Dhingra and also @Harsh Shrivastava , Please post some very hard, Classic Logic problems! Thank U!

Log in to reply

I would also like more problems in logic ( beta) part.... I have become level three in it, but now Very few questions are left to be done. I would also support this view because I would like more questions in this specific section...!!! Hope something will be done soon.😊😊😊

Log in to reply

nice

Log in to reply

Did any1 try harder cheryl's birthday

Log in to reply

How I am doing

Log in to reply