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Freaky Factorization!

Factorize \(27x^3- 81y^3 \).

Please show your steps and reason wherever needed.

Note by Palaash Barot
6 months, 4 weeks ago

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\[27x^3-81y^3=27(x^3-3y^3)\] You can factorize the second factor further by using the algebraic identity \(a^3-b^3=(a-b)(a^2+ab+b^2)\), only there won't be integral coefficients in the resulting factors: \[27(x^3-3y^3)=27(x-\sqrt[3]{3}y)(x^2+\sqrt[3]{3}xy+\sqrt[3]{9}y^2)\] Abdur Rehman Zahid · 6 months, 4 weeks ago

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@Abdur Rehman Zahid thanks for the help..... Palaash Barot · 6 months, 4 weeks ago

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