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Friends please solve and give the order and degree of the following differential equation

\( \left( dy/dx \right) \wedge \sqrt [ 2 ]{ 2 } =\quad x+1 \)

Note by Rajat Dwivedi
2 years, 6 months ago

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\( \left( dy/dx \right) \wedge \sqrt [ 2 ]{ 2 } =\quad x+1 \)

Enclose the LaTeX code in \( \) brackets. Also, do you mean \( \left (\dfrac{dx}{dy} \right)^ {\sqrt [ 2 ]{ 2 } }= x+1 \) Siddhartha Srivastava · 2 years, 6 months ago

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