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# Friends please solve and give the order and degree of the following differential equation

$$\left( dy/dx \right) \wedge \sqrt [ 2 ]{ 2 } =\quad x+1$$

Note by Rajat Dwivedi
2 years, 11 months ago

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$$\left( dy/dx \right) \wedge \sqrt [ 2 ]{ 2 } =\quad x+1$$

Enclose the LaTeX code in  brackets. Also, do you mean $$\left (\dfrac{dx}{dy} \right)^ {\sqrt [ 2 ]{ 2 } }= x+1$$

- 2 years, 11 months ago