# From the AQA GCSE exam today.

So in the last question, after using a couple of rules I know about triangles, I worked out that two triangles were similar but had different side lengths. The East side of the first triangle was X but equaled 1.2 on the other, the south side of the fist triangle was lenghth 4.8 and X on the other. I was wondering, was the way to work it out, to do X/4.8 = 1.2/X which works out to be X²=5.76 so X=2.4? I'm asking because none of my mates got it so i have nobody to discuss with :/

Note by Callum Goodall
3 years ago

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