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from which step does the error begins,and what is the error

step 1; a=b step 2; a^2=ab (multiplying both sides by a) step 3; a^2-b^2=ab-b^2 (subtracting both sides by b^2) step 4; (a+b)(a-b)=b(a-b) step 5; (a+b)=b (cancelling (a-b) from both sides) step 6; 2b=b (as a=b from step 1) therefore, 2=1 (cancelling b from both the side)

Note by Haque Farazul
4 years, 3 months ago

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thnx for answering Haque Farazul · 4 years, 3 months ago

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step 5 is wrong due to dividing by 0 Bhuvnesh Goyal · 4 years, 3 months ago

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step 5 is wrong because you are cancelling (a-b) from both sides which according to step 1 is equal to zero. Dividing by zero is incorrect. Surya Prakash · 4 years, 3 months ago

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@Surya Prakash yes the step 5 is incorrect and the procedure includes diving by 0 i.e.(a-b) is absolutely wrong...leading to wrong result...:) Raja Metronetizen · 4 years, 3 months ago

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