Find all natural numbers \(n\) such that \(n! | a^n+1 \) for all \(0\) <\( a \le n! \) with natural number \(a\).
Surya Prakash Bugatha
2 years, 4 months ago
Ehh, \(2^n+1\) is less than \(n!\) for \(n<4\), so you got only 3 cases to check...
Log in to reply
Hint: What happens when \( a = 0 \)?
Ooops!! Typo fixed
Hint: What happens when \( a = 1 \)? What happens when \( a = n \)?
@Sreejato Bhattacharya @Surya Prakash Bugatha