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Fun with factorials

Find all natural numbers \(n\) such that \(n! | a^n+1 \) for all \(0\) <\( a \le n! \) with natural number \(a\).

Note by Surya Prakash Bugatha
2 years, 1 month ago

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Ehh, \(2^n+1\) is less than \(n!\) for \(n<4\), so you got only 3 cases to check... Sreejato Bhattacharya · 2 years, 1 month ago

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Hint: What happens when \( a = 0 \)? Calvin Lin Staff · 2 years, 1 month ago

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@Calvin Lin Ooops!! Typo fixed Surya Prakash Bugatha · 2 years, 1 month ago

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@Surya Prakash Bugatha Hint: What happens when \( a = 1 \)? What happens when \( a = n \)? Calvin Lin Staff · 2 years, 1 month ago

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