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General Maths Problem 01

solve this problem

Note by Ajitesh Mishra
4 years, 7 months ago

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2 votes

  Easy Math Editor

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*italics* or _italics_ italics
**bold** or __bold__ bold

- bulleted
- list

  • bulleted
  • list

1. numbered
2. list

  1. numbered
  2. list
Note: you must add a full line of space before and after lists for them to show up correctly
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[example link](https://brilliant.org)example link
> This is a quote
This is a quote
    # I indented these lines
    # 4 spaces, and now they show
    # up as a code block.

    print "hello world"
# I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
MathAppears as
Remember to wrap math in \( ... \) or \[ ... \] to ensure proper formatting.
2 \times 3 \( 2 \times 3 \)
2^{34} \( 2^{34} \)
a_{i-1} \( a_{i-1} \)
\frac{2}{3} \( \frac{2}{3} \)
\sqrt{2} \( \sqrt{2} \)
\sum_{i=1}^3 \( \sum_{i=1}^3 \)
\sin \theta \( \sin \theta \)
\boxed{123} \( \boxed{123} \)

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Let \(X\) and \(Y\) be the heights of the big and small cylinder respectively. In figure B height of water in the small cylinder is inadvertently \(X-20\). So, the Volume occupied by water \(=\pi3^2X+\pi 1^2(20-X)\) \(\Rightarrow V=20\pi+8\pi X\) In figure \(C\) height of water in small cylinder is simply \(Y\) and that in the bigger one is\(28-Y\) In figure \(C\), \(V=\pi Y +9\pi (28-Y)\) \(\Rightarrow V=252\pi-8\pi Y\) Equating the two volume equations, gives us: \(20\pi+8\pi X=252\pi-8\pi Y\) \(\Rightarrow X+Y=29 cm\) which is the height of the bottle.

Aditya Parson - 4 years, 7 months ago

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(A) 29 cm of water. Using that volume of water is the same in figure b and figure c.

Aditya Parson - 4 years, 7 months ago

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