Please provide a solution to this problem.

\( ABCD \) is a trapezium with \(AD\) parallel to \(BC\); \(AD=3BC\) and a transversal \(XY\) cuts \(BC\) at \(X\) and \(AD\) at \(Y\). If \(EF\) is a line segment contained in \(XY\) such that \( AE\) is parallel \(DF\). \(BE\) parallel to \(CF\) and \(AE/DF=CF/BE=2\), show that area of the triangle \(EFD\) is equal to \(\dfrac14\) of the area of \(ABCD\).

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TopNewest@achal jain bhai is this problem from some book.. – Deepansh Jindal · 1 year ago

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– Achal Jain · 1 year ago

yeah from "Challenges of Pre College Mathematics".Log in to reply

@Chew-Seong Cheong – Achal Jain · 1 year ago

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