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Geometry Trouble!

Please provide a solution to this problem.

\( ABCD \) is a trapezium with \(AD\) parallel to \(BC\); \(AD=3BC\) and a transversal \(XY\) cuts \(BC\) at \(X\) and \(AD\) at \(Y\). If \(EF\) is a line segment contained in \(XY\) such that \( AE\) is parallel \(DF\). \(BE\) parallel to \(CF\) and \(AE/DF=CF/BE=2\), show that area of the triangle \(EFD\) is equal to \(\dfrac14\) of the area of \(ABCD\).

Note by Achal Jain
1 year, 4 months ago

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@achal jain bhai is this problem from some book..

Deepansh Jindal - 1 year, 4 months ago

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yeah from "Challenges of Pre College Mathematics".

Achal Jain - 1 year, 4 months ago

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@Chew-Seong Cheong

Achal Jain - 1 year, 4 months ago

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