Waste less time on Facebook — follow Brilliant.
×

Geonetry

square \(ABCD\) divided into 18 smaller square.
17 squares of the sides of length 1.
\(ABCD\) square area Find.

Note by Mahla Salarmohammadi
5 months, 2 weeks ago

No vote yet
1 vote

Comments

Sort by:

Top Newest

Let area of ABCD be \(x^2\) and area of the last of the 18 squares be \(y^2\).

We have \(x^2=17+y^2\) or \((x+y)(x-y)=17\). We must have \(x+y=17\) and \(x-y=1\).

Solving we get \(x=9\) and \(y=8\).

Therefore area of ABCD is \(9^2=81\). Svatejas Shivakumar · 5 months, 2 weeks ago

Log in to reply

@Svatejas Shivakumar Actually, x^2=17+y^2 if I'm not mistaken because there are seventeen squares of side length one. Therefore the area is 81. At least I know this case works because it can be drawn out. Maybe the wording messed one of us up. Sal Gard · 3 months, 2 weeks ago

Log in to reply

@Sal Gard Yes you are right thanks. Svatejas Shivakumar · 3 months, 2 weeks ago

Log in to reply

×

Problem Loading...

Note Loading...

Set Loading...