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# Geonetry

square $$ABCD$$ divided into 18 smaller square.
17 squares of the sides of length 1.
$$ABCD$$ square area Find.

9 months, 1 week ago

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Let area of ABCD be $$x^2$$ and area of the last of the 18 squares be $$y^2$$.

We have $$x^2=17+y^2$$ or $$(x+y)(x-y)=17$$. We must have $$x+y=17$$ and $$x-y=1$$.

Solving we get $$x=9$$ and $$y=8$$.

Therefore area of ABCD is $$9^2=81$$. · 9 months, 1 week ago

Actually, x^2=17+y^2 if I'm not mistaken because there are seventeen squares of side length one. Therefore the area is 81. At least I know this case works because it can be drawn out. Maybe the wording messed one of us up. · 7 months, 1 week ago