I've noticed some odd behavior for the leaderboard of a set.

Usually, for a set of problems, you solve the problems "inside" the set - you click on the set, then you click on the problem you want to solve.

But you can also solve problems "outside" the set, i.e. you can get to a problem inside the set without clicking on the set. (Either the problem was already posted, or a problem inside the set gets reshared.)

What I've noticed is that if even you solve all the problems in a set, if you solve your last problem "outside" the set, then you don't get on the leaderboard. I feel like how you solve the problems of a set should not impact whether you make the leaderboard or not.

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TopNewestYeah, the whole thing is really funky. – Finn Hulse · 2 years, 5 months ago

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There's one more problem. The leader-board should change when the set changes. For eg., some people had solved my set when it had only one problem. But now it has 100 problems. The person is still on the LB, this kinda sucks.. – Satvik Golechha · 2 years, 1 month ago

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Yeah, I completely agree! – Geoff Pilling · 5 months, 3 weeks ago

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– Ashish Siva · 4 months, 2 weeks ago

TotallyLog in to reply

I just now noticed that. I solved the "Bulging Box" problem, as shared by Endow, thus completing his set of problems, but the leaderboard remains dead. I have no idea who else has completed the set. – Michael Mendrin · 2 years, 4 months ago

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I agree, though is it possible that you just didn't click update my score? – Rmflute Shrivastav · 1 year, 6 months ago

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Mr Haussmann may i please have your email as i want to ask your advice about some part in combinatorics – Abdelhameed Nasser · 2 years, 1 month ago

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– Jon Haussmann · 2 years, 1 month ago

For privacy reasons, I do not give out my e-mail address. However, if you submit your question as a post, I can try to answer it.Log in to reply

– Abdelhameed Nasser · 2 years, 1 month ago

https://brilliant.org/community-problem/challenging-interesting-combinatorics-problem/ for the problem attached in this link what would be if the number is 100 employees and salary from 1 to 100. or What model you used to solve this problem? Thank you.Log in to reply