Goldbach Conjecture states that" Every even integer greater than 2 can be written as sum of two primes"

I think this might be a proof.

Let a number be 2k and let the two primes be 2n+1 and 2m+1. Therefore, 2k=2(m+n+1) k=m+n+1

Therefore, there are infinite many solutions and one of them satisfies the given equation. Goldbach conjecture is true. All who think this is wrong , please comment and make me realize my mistake

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TopNewestYou can find infinitely many solutions for some random m and n. But how do you know you can find infinitely many solutions such that 2m + 1 and 2n + 1 are both prime? – Sandhya Saravanan · 1 year, 2 months ago

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– Sudhir Aripirala · 1 year, 2 months ago

there are infinite but only one satisfies itLog in to reply

– Sandhya Saravanan · 1 year, 1 month ago

How do you know that there will be one for sure that will satisfy it? What if there are none?Log in to reply

What is n and m? How do you determine them for a given k? E.g. If \( k = 1000000000 \), what is \(n, m \)? – Calvin Lin Staff · 1 year, 8 months ago

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@Calvin Lin – Sudhir Aripirala · 5 months, 2 weeks ago

I understood my mistakeLog in to reply

– Calvin Lin Staff · 5 months, 2 weeks ago

That's great! Understanding your own mistakes is the first step towards discovering new facts!Log in to reply

– Sudhir Aripirala · 1 year, 8 months ago

I meant that prime is odd, so they can written in the form of 2n+1 and 2m+1. By the conjecture, let the sum of two numbers is a even number 2k=2m+2n+2 that is equal to k=m+n+1Log in to reply