Waste less time on Facebook — follow Brilliant.
×

Gravitation

We all know that the gravitational field inside a thin spherical shell is zero. There are different methods to prove this. I came across one such odd yet amazing method . I would like everyone to try proving it by this method .I will put my proof in a couple of days.

Zero force inside a sphere.

Show that the gravitational force inside a spherical shell is zero by showing
that the pieces of mass at the ends of the thin cones in the figure give
canceling forces at point P (any point inside the sphere).

Note by Ayush Shridhar
1 year, 9 months ago

No vote yet
1 vote

  Easy Math Editor

MarkdownAppears as
*italics* or _italics_ italics
**bold** or __bold__ bold

- bulleted
- list

  • bulleted
  • list

1. numbered
2. list

  1. numbered
  2. list
Note: you must add a full line of space before and after lists for them to show up correctly
paragraph 1

paragraph 2

paragraph 1

paragraph 2

[example link](https://brilliant.org)example link
> This is a quote
This is a quote
    # I indented these lines
    # 4 spaces, and now they show
    # up as a code block.

    print "hello world"
# I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
MathAppears as
Remember to wrap math in \( ... \) or \[ ... \] to ensure proper formatting.
2 \times 3 \( 2 \times 3 \)
2^{34} \( 2^{34} \)
a_{i-1} \( a_{i-1} \)
\frac{2}{3} \( \frac{2}{3} \)
\sqrt{2} \( \sqrt{2} \)
\sum_{i=1}^3 \( \sum_{i=1}^3 \)
\sin \theta \( \sin \theta \)
\boxed{123} \( \boxed{123} \)

Comments

Sort by:

Top Newest

What was your method?

Aditya Kumar - 1 year, 9 months ago

Log in to reply

same can you prove the same thing for an ellipsoid?

Ayush Shridhar - 1 year, 9 months ago

Log in to reply

Ellipsoid will be having the same proof. There'll be a change in diagram. Rest all will be the same thing.

Aditya Kumar - 1 year, 9 months ago

Log in to reply

I'll try that also. Thanks for enlightening.

Aditya Kumar - 1 year, 9 months ago

Log in to reply

The tougher task is doing the same thing for an ellipsoid. I am trying to prove that! Might take a couple of days.

Ayush Shridhar - 1 year, 9 months ago

Log in to reply

×

Problem Loading...

Note Loading...

Set Loading...