Let \(ABCD\) be a trapezoid, such that the sides \(AB\) and \(CD\) are parallel and the length of the diagonal \(BD\) is equal to the sum of the lengths of the sides \(AB\) and \(CD\). Let \(M\) be the midpoint of the side \(BC\) and let \(E\) be the symmetric of \(C\) in respect to \(DM\).

Show that angle \( AEB\) is equal to angle \(ACD\).

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