Could you guys post links to the hardest problem you have ever encountered on Brilliant? That way users who are hunting for difficult problems can solve them and boost their rating. Please do not post answers.

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There was a number theory before the site was revamped, one that dealt with remainders modulus 19 and included three variables (unknowns, k,a,b based on certain restrictions though). The only answer I saw for that question had an incomplete proof, so that should be sufficient evidence for its difficulty. If anybody here is able to find it...

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## Comments

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TopNewestHi Finn,

I thought this problem was breathtakingly beautiful in it's simplicity.

I'll ask around the office and see if we can dig up a historically absurdly difficult problem for you to look at.

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This probl em is truly mesmerizing.

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This is really a nice problem.I couldn't take up the courage 2 write d correct answer as i was nt sure 4 it.

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Thanks!

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Yeah that one was crazy hard... I mean seriously! That took me forever! ;)

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I Love this problem, took me so long to get the courage to type in the answer

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Yeah, Ryan sums it up pretty well right here.

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This....is.....HILARIOUS!!! :D

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Try this one out: https://brilliant.org/community-problem/an-interesting-problem-264/?group=iiMQMGYWAfX2

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Cool.

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Hi,this problem is deleted so could anyone tell me what was it?

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Exactly, what was it about?

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We are pretty sure this is the hardest algebra problem on Brilliant. Could be wrong though, ratings are a dynamic thing.

Edit: I bungled the link the first time it should work now.

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Wow a problem with over 3000 rating O.o

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That's right, I kneel down when I see this problem...

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Holy moly. \Tries to solve

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Maybe hard. https://brilliant.org/community-problem/strokes/?group=HdtDpoEPM9Zd&ref_id=88876

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Personally thought this algebra problem was particularly difficult :P

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Also, just for fun, you can post a ridiculously easy problem.

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There you go , my friend!! :D

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ridiculuously easy..... x^2 >= xy >= y^2 show that 9(x^2)+6(xy)+(y^2) >= 0

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Can someone post the hardest Combinatorics problem they've come across?

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Hi Jose,

I don't think this is the hardest combinatorics problem on Brilliant, but this one is relatively recent and rated quite high.

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There was a number theory before the site was revamped, one that dealt with remainders modulus 19 and included three variables (unknowns, k,a,b based on certain restrictions though). The only answer I saw for that question had an incomplete proof, so that should be sufficient evidence for its difficulty. If anybody here is able to find it...

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Knock yourself out:

You won't do it.

Noone's done it.

You might do it.

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(-1)^π

Hardest problem...

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