In \(\Delta ABC\), \(D\), \(E\), \(F\) are such that \(B - D - C\), \(C - E - A\), \(A - F - B\). \(\overline{AD}\), \(\overline{BE}\), \(\overline{CF}\) are concurrent at \(P\) which is in the interior of \(\Delta ABC\). Ray \(FE\) intersects ray \(BC\) at \(N\). \(\overline{AD}\) intersects \(\overline{FE}\) at \(M\). Given \(FM = 3\), \(ME = 2\) find \(NE\).

Can anyone give me a trigonometric solution for this?

This is part of the set Trigonometry.

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Can you tell me how you got the solution?

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