# Help!!!

Give a solution please......

Note by Math Man
3 years, 5 months ago

MarkdownAppears as
*italics* or _italics_ italics
**bold** or __bold__ bold
- bulleted- list
• bulleted
• list
1. numbered2. list
1. numbered
2. list
Note: you must add a full line of space before and after lists for them to show up correctly
paragraph 1paragraph 2

paragraph 1

paragraph 2

[example link](https://brilliant.org)example link
> This is a quote
This is a quote
    # I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
# I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
MathAppears as
Remember to wrap math in $$...$$ or $...$ to ensure proper formatting.
2 \times 3 $$2 \times 3$$
2^{34} $$2^{34}$$
a_{i-1} $$a_{i-1}$$
\frac{2}{3} $$\frac{2}{3}$$
\sqrt{2} $$\sqrt{2}$$
\sum_{i=1}^3 $$\sum_{i=1}^3$$
\sin \theta $$\sin \theta$$
\boxed{123} $$\boxed{123}$$

Sort by:

Case 1. X> 0. Let the floor of X be A.

Then A (A+1)> 2013> A (A). If A> 44, the right side is not satisfied. If A <45, then the left side is not satisfied. No solutions in this case.

Case 2. X <0. (Again, let the floor of X be A)

Then $$A^{2}> 2013 >A(A+1)$$.

Note that A=-45 is the only solution. This gives x=$$-\frac {2013}{45}$$ as the only solution.

- 3 years, 5 months ago

Well dude still I'didn't get 2013 as the asnwer even by using a calculator.

- 3 years, 5 months ago

You might be mistaken. $$\lfloor -\frac{2013}{45} \rfloor = \lfloor -44.7333 \ldots \rfloor = -45$$ instead of $$-44$$ as you might have thought. You can then see that $$x \lfloor x \rfloor = 2013$$ very easily.

- 3 years, 5 months ago

Thanks...got the right nerve

- 3 years, 5 months ago

44

- 3 years, 5 months ago

thank you

- 3 years, 5 months ago

It is not complete, as the case for x <0 was not considered. There is one solution, as shown in my solution above.

- 3 years, 5 months ago

jessen wkwkwkw:D

- 3 years, 5 months ago

lol

- 3 years, 5 months ago