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Help!!!

Give a solution please......

Note by Math Man
2 years, 2 months ago

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Case 1. X> 0. Let the floor of X be A.

Then A (A+1)> 2013> A (A). If A> 44, the right side is not satisfied. If A <45, then the left side is not satisfied. No solutions in this case.

Case 2. X <0. (Again, let the floor of X be A)

Then \(A^{2}> 2013 >A(A+1)\).

Note that A=-45 is the only solution. This gives x=\(-\frac {2013}{45}\) as the only solution. Joel Tan · 2 years, 2 months ago

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@Joel Tan Well dude still I'didn't get 2013 as the asnwer even by using a calculator. Jaiveer Shekhawat · 2 years, 2 months ago

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@Jaiveer Shekhawat You might be mistaken. \(\lfloor -\frac{2013}{45} \rfloor = \lfloor -44.7333 \ldots \rfloor = -45\) instead of \(-44\) as you might have thought. You can then see that \(x \lfloor x \rfloor = 2013\) very easily. Jake Lai · 2 years, 2 months ago

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@Jake Lai Thanks...got the right nerve Jaiveer Shekhawat · 2 years, 2 months ago

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44

44

Jaiveer Shekhawat · 2 years, 2 months ago

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@Jaiveer Shekhawat thank you Math Man · 2 years, 2 months ago

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@Math Man It is not complete, as the case for x <0 was not considered. There is one solution, as shown in my solution above. Joel Tan · 2 years, 2 months ago

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jessen wkwkwkw:D Alfian Edgar · 2 years, 2 months ago

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@Alfian Edgar lol Math Man · 2 years, 2 months ago

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