@Pranjal Jain
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\(\text{angular velocity}=\dfrac{\text{Relative velocity perpendicular to line joining them}}{\text{Distance between them}}\)

By simple geometry, \(\angle AOP=30^\circ\)

Case I: \(A\) is fixed to ground, so, the velocity of \(P\) will be \(\omega R\) at angle \(120^\circ\) to the line joining \(AP\), thus, \(\omega_1=\dfrac{\omega R\cos 30^\circ}{\sqrt{3}R}\)

Case II: \(A\) is fixed to disc, in this case, velocity of \(A\) will add up in relative velocity. In this case also, velocity of \(A\) will be \(\omega R\) at angle \(60^\circ\) to the line joining \(AP\). Thus, \(\omega_2=\dfrac{\omega R\cos 30^\circ+\omega R\cos 30^\circ}{\sqrt{3}R}=2\omega_1\Rightarrow \dfrac{\omega_1}{\omega_2}=\dfrac{1}{2}\)
–
Pranjal Jain
·
1 year, 9 months ago

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@Pranjal Jain
–
Well indeed very nice by the way how was ur mains exam
–
Kyle Finch
·
1 year, 9 months ago

## Comments

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TopNewest@Raghav Vaidyanathan the problem is in the middle. – Kyle Finch · 1 year, 9 months ago

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– Pranjal Jain · 1 year, 9 months ago

I have rotated the image. \(\huge\ddot\smile\)Log in to reply

– Kyle Finch · 1 year, 9 months ago

U can tell me the solution . ???Log in to reply

– Pranjal Jain · 1 year, 9 months ago

A disc has an angular velocity?Log in to reply

By simple geometry, \(\angle AOP=30^\circ\)

Case I:\(A\) is fixed to ground, so, the velocity of \(P\) will be \(\omega R\) at angle \(120^\circ\) to the line joining \(AP\), thus, \(\omega_1=\dfrac{\omega R\cos 30^\circ}{\sqrt{3}R}\)Case II:\(A\) is fixed to disc, in this case, velocity of \(A\) will add up in relative velocity. In this case also, velocity of \(A\) will be \(\omega R\) at angle \(60^\circ\) to the line joining \(AP\). Thus, \(\omega_2=\dfrac{\omega R\cos 30^\circ+\omega R\cos 30^\circ}{\sqrt{3}R}=2\omega_1\Rightarrow \dfrac{\omega_1}{\omega_2}=\dfrac{1}{2}\) – Pranjal Jain · 1 year, 9 months agoLog in to reply

– Kyle Finch · 1 year, 9 months ago

Well indeed very nice by the way how was ur mains examLog in to reply

– Pranjal Jain · 1 year, 9 months ago

Not too good. Getting just 275.Log in to reply

– Kyle Finch · 1 year, 9 months ago

Was the physics section tough??Log in to reply

– Pranjal Jain · 1 year, 9 months ago

It was NCERTish. I must not blame questions for my marks. I don't like EM.Log in to reply

– Kyle Finch · 1 year, 9 months ago

So who among all of you is supposed to get the highest.Log in to reply

– Pranjal Jain · 1 year, 9 months ago

Ronak Agrawal (on Brilliant)Log in to reply

– Kyle Finch · 1 year, 9 months ago

Ok just one last query what makes a problem popular on brilliant. Can u tell ronaks scoreLog in to reply

– Pranjal Jain · 1 year, 9 months ago

He's getting like 315-320. The quality of problem makes it popular!Log in to reply

– Parth Lohomi · 1 year, 9 months ago

Bhavya Is getting 322.I guess??Log in to reply

– Pranjal Jain · 1 year, 9 months ago

Yes, he doesLog in to reply

– Kyle Finch · 1 year, 9 months ago

No i m asking do the staff member decide or the moderatorsLog in to reply

– Kyle Finch · 1 year, 9 months ago

\(\omega\)Log in to reply