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# help

The sum of series upto 10 terms $$\frac{x}{1-x^2}+\frac{x^2}{1-x^4}+\frac{x^4}{1-x^8}+....~is~\frac{1}{1-x}-\frac{1}{1-x^p}$$. Find p

Note by Kyle Finch
1 year, 6 months ago

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$\frac{1}{1-x}-\frac{1}{1-x^{1024}}$

$$\Rightarrow p=1024$$

In each term, add one and subtract one from numerator. Then split term into two and you will see that it is a telescopic series. · 1 year, 6 months ago

Thanx man for the help. · 1 year, 6 months ago

the general term of series cannot be determined · 1 year, 6 months ago

it has its answer as p=1024 · 1 year, 6 months ago

Raghav Vaidyanathan Brian Charlesworth plz help · 1 year, 6 months ago

@Brian Charlesworth · 1 year, 6 months ago