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The sum of series upto 10 terms \(\frac{x}{1-x^2}+\frac{x^2}{1-x^4}+\frac{x^4}{1-x^8}+....~is~\frac{1}{1-x}-\frac{1}{1-x^p}\). Find p

Note by Kyle Finch 2 years, 5 months ago

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The answer is

\[\frac{1}{1-x}-\frac{1}{1-x^{1024}}\]

\(\Rightarrow p=1024\)

In each term, add one and subtract one from numerator. Then split term into two and you will see that it is a telescopic series.

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Thanx man for the help.

the general term of series cannot be determined

it has its answer as p=1024

Raghav Vaidyanathan Brian Charlesworth plz help

@Brian Charlesworth

@Raghav Vaidyanathan

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TopNewestThe answer is

\[\frac{1}{1-x}-\frac{1}{1-x^{1024}}\]

\(\Rightarrow p=1024\)

In each term, add one and subtract one from numerator. Then split term into two and you will see that it is a telescopic series.

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Thanx man for the help.

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the general term of series cannot be determined

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it has its answer as p=1024

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Raghav Vaidyanathan Brian Charlesworth plz help

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@Brian Charlesworth

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@Raghav Vaidyanathan

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