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The sum of series upto 10 terms $$\frac{x}{1-x^2}+\frac{x^2}{1-x^4}+\frac{x^4}{1-x^8}+....~is~\frac{1}{1-x}-\frac{1}{1-x^p}$$. Find p

Note by Kyle Finch
3 years, 1 month ago

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$\frac{1}{1-x}-\frac{1}{1-x^{1024}}$

$$\Rightarrow p=1024$$

In each term, add one and subtract one from numerator. Then split term into two and you will see that it is a telescopic series.

- 3 years, 1 month ago

Thanx man for the help.

- 3 years, 1 month ago

the general term of series cannot be determined

- 3 years, 1 month ago

it has its answer as p=1024

- 3 years, 1 month ago

Raghav Vaidyanathan Brian Charlesworth plz help

- 3 years, 1 month ago

- 3 years, 1 month ago