The sum of series upto 10 terms \(\frac{x}{1-x^2}+\frac{x^2}{1-x^4}+\frac{x^4}{1-x^8}+....~is~\frac{1}{1-x}-\frac{1}{1-x^p}\). Find p

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TopNewestThe answer is

\[\frac{1}{1-x}-\frac{1}{1-x^{1024}}\]

\(\Rightarrow p=1024\)

In each term, add one and subtract one from numerator. Then split term into two and you will see that it is a telescopic series. – Raghav Vaidyanathan · 1 year, 6 months ago

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– Kyle Finch · 1 year, 6 months ago

Thanx man for the help.Log in to reply

the general term of series cannot be determined – Raghav Vaidyanathan · 1 year, 6 months ago

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– Kyle Finch · 1 year, 6 months ago

it has its answer as p=1024Log in to reply

Raghav Vaidyanathan Brian Charlesworth plz help – Kyle Finch · 1 year, 6 months ago

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@Brian Charlesworth – Kyle Finch · 1 year, 6 months ago

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@Raghav Vaidyanathan – Kyle Finch · 1 year, 6 months ago

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