# Help

Note by Ankit Kumar Jain
1 year, 2 months ago

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I was reading the wiki On AM - GM Inequality .In it I found out that there was a proof which said that it requires a bit of combinatorics . In the last bit of the proof , it said

$$k > m_g > 0 \Rightarrow m_g \in {(0 , k)}$$

$$k \geq m_a > 0 \Rightarrow m_a \in {(0 , k]}$$.

From these how does it follow that $$m_a \geq m_g$$ ?

- 1 year, 2 months ago

- 1 year ago

I don't know what $$k, m_a$$ and $$m_g$$ represents. So I can't help you with that...

- 1 year ago

AM-GM .In the proof that says 'It requires a bit of combinatorics' , that one.

- 1 year ago

Where? I don't know which book or article you are looking at...

- 1 year ago

I have posted the link to the source right in my previous comment. It is the brilliant wiki page on AM- GM Inequality.

- 1 year ago

Sir $$m_a$$ is the arithmetic mean and $$m_g$$ is geometric mean and $$k$$ is some constant.

- 1 year ago

@Calvin Lin Sir , recently I posted two questions ..the problem name changed automatically.

Like I named the problem 'Strange' , it changed to 'A geometry problem by Ankit Kumar Jain.

- 1 year, 2 months ago

We remove titles that are meaningless to the problem.

Staff - 1 year, 2 months ago

Okay sir .

Sir , can you please suggest some name for the problem I mentioned above so that I can get some idea and I can try to give names that are meaningful from next time.

- 1 year, 2 months ago

Sir, So will you write the feedback on the solution or is the feature removed?

- 1 year, 2 months ago

The functionality of "request feedback from challenge master" has been removed.

Staff - 1 year, 2 months ago

We have removed that functionality.

Staff - 1 year, 2 months ago